No . but she can buy 2 of the books but not all 3
Answer:the cost of one day lily = $9 and cost of one pot of ivy = $2
Step-by-step explanation:
Step 1
let day lilies be rep as d
and ivy be represented as i
So that The expression for what Willie spent on 12 day lilies and 4 pots of ivy = $116 be
12 d+ 4i = 116 ---- equation 1
and for Anjali spending $60 on 6 day lilies and 3 pots of ivy be
6d+ 3i = $60------ equation 2
Step 2 --- Solving
12 d+ 4i = 116 ---- equation 1
6d+ 3i = $60------ equation 2
Multiply equation 2 by (2) and subtracting equation 1 from it
12d+ 6i= 120
--12 d+ 4i = 116
2 i= 4
i = 4/2 = 2
TO find d, putting the value of i = 2 in equation 1 and solving
12d+ 4(2) = 116
12d= 116-8
12d= 108
d= 108/12= 9
Therefore the cost of one day lily = $9 and cost of one pot of ivy = $2
Answer:
Root( c square -9)
Step-by-step explanation:
The answer u have is the answer for a^2
Solve for <em>x</em> when √(<em>x</em> ² - 4) = 1 :
√(<em>x</em> ² - 4) = 1
<em>x</em> ² - 4 = 1
<em>x</em> ² = 5
<em>x</em> = ±√5
We're looking at <em>x </em>≤ 0, so we take the negative square root, <em>x</em> = -√5.
This means <em>f</em> (-√5) = 1, or in terms of the inverse of <em>f</em>, we have <em>f</em> ⁻¹(1) = -√5.
Now apply the inverse function theorem:
If <em>f(a)</em> = <em>b</em>, then (<em>f</em> ⁻¹)'(<em>b</em>) = 1 / <em>f '(a)</em>.
We have
<em>f(x)</em> = √(<em>x</em> ² - 4) → <em>f '(x)</em> = <em>x</em> / √(<em>x</em> ² - 4)
So if <em>a</em> = -√5 and <em>b</em> = 1, we get
(<em>f</em> ⁻¹)'(1) = 1 / <em>f '</em> (-√5)
(<em>f</em> ⁻¹)'(1) = √((-√5)² - 4) / (-√5) = -1/√5
The sign must be negative; see the attached plot, and take note of the negatively-sloped tangent line to the inverse of <em>f</em> at <em>x</em> = 1.
Answer:
The width is 
Step-by-step explanation:
The perimeter of the rectangular yoga mat can be found using the formula;
.
.
It was given that the width of the mat is eight less than half the length.

We put equation (2) into equation (1) to get;
.
.
.

Divide both sides by 3;

We put
into equation 2 to get;


