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3 years ago

13

Solve for t 6t=30 math

2 answers:

alexira [117]3 years ago

7 0

Answer:

T = 5

Step-by-step explanation:

the answer can be found by simply dividing the product by the given factor, in this case (6) 30 / 6 = 5

lesya [120]3 years ago

4 0

$⟹\sf \: 6t = 30$

$⟹\sf \: Substitute \: the \: value \: of \: t \: as \: 30/6 \: in \: the \: above \: equation.$

$\sf \: 6t = 30 \\ \sf \: t = \frac{30}{6} \\ \sf \: t = 5$

Answer ⟶ $\boxed{\bf{t = 5}}$

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Of the 8 students in the chess club, three will represent the club at an upcoming competition. How many different 3-person teams

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3 years ago

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2 years ago

let X represent the amount of time till the next student will arriv ein the library partking lot at the university. If we know t

AlekseyPX

Answer:

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

Mean of 4 minutes

This means that $m = 4, \mu = \frac{1}{4} = 0.25$

Find the probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot:

This is:

$P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2)$

In which

$P(X \leq 132) = 1 - e^{-0.25*132} = 1$

$P(X \leq 2) = 1 - e^{-0.25*2} = 0.393469$

$P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2) = 1 - 0.393469 = 0.606531$

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

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3 years ago

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