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iragen [17]
3 years ago
13

Solve for t 6t=30 math

Mathematics
2 answers:
alexira [117]3 years ago
7 0

Answer:

T = 5

Step-by-step explanation:

the answer can be found by simply dividing the product by the given factor, in this case (6)  30 / 6 = 5

lesya [120]3 years ago
4 0

⟹\sf \: 6t = 30

⟹\sf \: Substitute \: the \: value \: of \: t \: as \: 30/6 \: in \: the \: above \: equation.

\sf \: 6t = 30 \\ \sf \: t =  \frac{30}{6}  \\ \sf \: t = 5

Answer ⟶ \boxed{\bf{t = 5}}

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3 years ago
Of the 8 students in the chess club, three will represent the club at an upcoming competition. How many different 3-person teams
xz_007 [3.2K]
I think that this is a combination problem. From the given, the 8 students are taken 3 at a time. This can be solved through using the formula of combination which is C(n,r) = n!/(n-r)!r!. In this case, n is 8 while r is 3. Hence, upon substitution of the values, we have

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6 0
3 years ago
Read 2 more answers
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uranmaximum [27]

Answer:

ok....let me try .....

  • ohhhh leave it. gu

<h2>..ok bro....sorry don't be angry <em><u>b</u></em><em><u>j</u></em><em><u>h</u></em><em><u>u</u></em><em><u>j</u></em><em><u>j</u></em></h2>
6 0
2 years ago
let X represent the amount of time till the next student will arriv ein the library partking lot at the university. If we know t
AlekseyPX

Answer:

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

Mean of 4 minutes

This means that m = 4, \mu = \frac{1}{4} = 0.25

Find the probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot:

This is:

P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2)

In which

P(X \leq 132) = 1 - e^{-0.25*132} = 1

P(X \leq 2) = 1 - e^{-0.25*2} = 0.393469

P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2) = 1 - 0.393469 = 0.606531

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

4 0
3 years ago
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