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earnstyle [38]
3 years ago
10

What is the solution of -3 = x +5

Mathematics
1 answer:
drek231 [11]3 years ago
4 0
X=-8

A negative plus a positive, if ghe negative is bigger it stays negative. -8 is bigger than 5 and 8 - 5 is 3 add the negative and you get -3
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Find the intercepts.<br> . (-1,5) and (-3,-5)
Firdavs [7]

Answer:

x-intercept: (-2, 0), y-intercept: (0, 10)

Step-by-step explanation:

First, we need to find the equation of this line. The formula to find the slope is:(y1-y2)/(x1-x2). Substituting the real numbers for this formula, (5-(-5))=10, (-1-(-3)=2. 10/2=5.

This means that the slope of this line is 5.

To find the complete equation for this line, we just need to plug in the x-value and add whatever needs to be added to attain the y-value. (You can plug in any x-value/y-value available.)

5=5(-1)+?

-5+<u>10</u>=5.

The complete equation for this line is y=5x+10.

From here, the y-intercept is easy, because the number after the coefficient and variable (5 and x) are before the y-intercept (in standard form). The <em><u>y-intercept is (0, 10)</u></em> because if you plug in 0 for the x-value, you will get 10 as your y-value.

On the other hand, if you plug in 0 for your y-value and solve it out, you will get the x-intercept.

0=5x+10

-10=5x

x=-2

So the <em><u>x-intercept is (-2, 0)</u></em>.

5 0
3 years ago
Pluto is approximately 2.7 miles from the Sun.
4vir4ik [10]

Answer:

40 times greater

Step-by-step explanation:

5 0
3 years ago
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How are the semicircle and the diameter of a circle related?
k0ka [10]

Answer:

rThe degree of measure of the simicircle are the same.

Step-by-step explanation:

Im almost positive this is right..

3 0
2 years ago
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Please Help!
Artist 52 [7]
X<4 hope this helped dude
5 0
3 years ago
The researchers are concerned that the dollars spent per shopper examined in the study is too different from what has been found
Katarina [22]

Answer:

Step-by-step explanation:

Hello!

To study if the average dollars spend per shopper is different than the expected population average of $84.5 there was a sample of 120 shoppers taken and their spending habit registered.

Then the study variable is:

X: Amount of money spent by a shopper ($)

This population standard deviation is σ= $16

Using the data information I've run a normality test, with p-value: 0.3056 against the test significance level α: 0.05, the decision is to not reject the null hypothesis so there is enough statistical evidence to conclude that the study variable has a normal distribution.

X~N(μ;σ²)

I've also calculated the sample mean and standard deviation:

X[bar]= $81.01

S= $19.62

a.

If the objective is to test that the true mean spending for the population is significantly different than the expected average of 84.5, the parameter of interest is the population mean μ and the hypothesis test will be two-tailed.

H₀: μ = 84.5

H₁: μ ≠ 84.5

α:0.05

The statistic is a standard normal for one sample:

Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~N(0;1)

Z_{H_0}= \frac{81.01-84.5}{\frac{16}{\sqrt{120} } } = -2.389

p-value two tailed  0.016894

b.

The decision rule using the p-value method is:

If p-value ≤ α ⇒ Reject the null hypothesis.

If p-value > α ⇒ Do not reject the null hypothesis.

Since the p-value is less than the significance level, the decision is to reject the null hypothesis.

c.

Using a level of significance of 5% the null hypothesis was rejected. So there is enough statistical evidence to support the researcher's claim that the true mean spending for the population is significantly different than the expected average of $84.5.

I hope it helps!

3 0
3 years ago
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