Answer: The distance between the points (-6,7) and (-1,-5) is 13 units.
Solution:
P1=(-6,7)=(x1,y1)→x1=-6, y1=7
P2=(-1,-5)=(x2,y2)→x2=-1,y2=-5
Distance between points P1 and P2: d=?
d=sqrt [ (x2-x1)^2 + (y2-y1)^2 ]
Replacing the knwon values:
d=sqrt [ (-1-(-6))^2 + (-5-7)^2 ]
d=sqrt [ (-1+6)^2 + (-12)^2 ]
d=sqrt [ (5)^2 + 144 ]
d=sqrt [ 25 + 144 ]
d=sqrt [ 169 ]
d=13
-- They are unequal
-- The area of the circle is (pi) (radius²) = 19.63 inches² .
-- The area of the square is (side length)² = 25 inches² .
-- The area of the square is 27.3% greater than the area of the circle.
<h3><u>
Answer:</u></h3>
Below!
<h3><u>
Step-by-step explanation:</u></h3>
<u>You can take 25 as one example and 49 as the second example.</u>
Let's factorize.
- => 25 = 5 x 5 = 5² (Which is odd)
- => 49 = 7 x 7 = 7² (Which is odd)
<h3><u>Conclusion:</u></h3>
Hence, the statement is not true.
Hoped this helped.
Answer:
Step-by-step explanation:
The formula for determining the distance between two points on a straight line is expressed as
Distance = √(x2 - x1)² + (y2 - y1)²
Where
x2 represents final value of x on the horizontal axis
x1 represents initial value of x on the horizontal axis.
y2 represents final value of y on the vertical axis.
y1 represents initial value of y on the vertical axis.
From the given information,
x2 = - 1
x1 = 4
y2 = 6
y1 = 3
Therefore,
Distance = √(- 1 - 4)² + (6 - 3)²
Distance = √(- 5² + 3²) = √(25 + 9) = √34
Distance = 5.83
