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suter [353]
3 years ago
12

Taylor has saved $99 for a tablet. That is 45% of the cost of the tablet. How much does the tablet cost?

Mathematics
2 answers:
Fynjy0 [20]3 years ago
8 0

Answer:

$220 is the cost of the tablet

Step-by-step explanation:

99 divided by .45= 220

gayaneshka [121]3 years ago
7 0

Answer:

$220

Step-by-step explanation:

Make a proportion

We know that 99 over some number (x) must equal 45%

99/x=45/100

Cross multiply

45x=9,900

Divide by 45 on both sides

x=220

So, the tablet costs $220

Hope this helps! :)

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Answer:

1. tan (4π/3) = √3

Answered by GAUTHMATH

5 0
3 years ago
Use the distributive property -5 {x + 4} + -3x + -9x + -7
grin007 [14]

Answer:

-17x - 27

Step-by-step explanation:

Distributive property is the multiplication of the number outside the parenthesis and the ones inside.

-5(x + 4) + -3x + -9x + -7

-5x - 20 + -3x + -9x + -7

Combine like terms:

-5x - 20 + -3x + -9x + -7

-5x +-3x

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Hope this helped.

8 0
3 years ago
On a cold day, hailstones fall with a velocity of 2i − 6k m s−1 . If a cyclist travels through the hail at 10i m s−1 , what is t
Paraphin [41]

Answer:

The velocity of the hail relative to the cyclist is V_{hc}=-8\hat{i}-6\hat{k}

The angle at which hailstones falling relative to the cyclist is \theta = 36.86^\circ

Step-by-step explanation:

Given : On a cold day, hailstones fall with a velocity of 2\hat{i}-6\hat{k}\text{ m/s} . If a cyclist travels through the hail at 10\hat{i} \text{ m/s}.

To find : What is the velocity of the hail relative to the cyclist and At what angle are the hailstones falling relative to the cyclist?

Solution :

The velocity of the hailstone falls is V_h=2\hat{i}-6\hat{k}\text{ m/s}

The velocity of the cyclist travels through the hail is V_c=10\hat{i} \text{ m/s}

The velocity of the hail relative to the cyclist is given by,

V_{hc}=V_h-V_c

Substitute the value in the formula,

V_{hc}=2\hat{i}-6\hat{k}-10\hat{i}

V_{hc}=-8\hat{i}-6\hat{k}

So, The velocity of the hail relative to the cyclist is V_{hc}=-8\hat{i}-6\hat{k}

Now, The angle of hails falling relative to the cyclist is given by

\theta = \tan^{-1}(\frac{-6}{-8})

\theta = \tan^{-1}(\frac{3}{4})

\theta = 36.86^\circ

So, The angle at which hailstones falling relative to the cyclist is  \theta = 36.86^\circ

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