Two lines intersecting at a right angle

An economy pack of highlighters contains 12 yellow, 6 blue, 4 green, and 3 orange highlighters. An experiment consists of random

Serhud [2]

Answer:

The probability of choosing a blue or yellow highlighter when one yellow highlighter is picked is 17/25.

Step-by-step explanation:

Here, according to the question:

Total number of yellow highlighters = 12

Total number of blue highlighters = 6

Total number of green highlighters = 4

Total number of orange highlighters = 3

So, the total number of highlighters = 12 + 6 + 4 + 3 = 25

Let E1 : Event of selecting a yellow highlighter.

P(E1) = $\frac{\textrm{Total number of yellow highlighters}}{\textrm{Total Highlighters}}$ = $\frac{12}{25}$

Let E2 : Event of selecting blue or yellow highlighter ONCE yellow highlighter is selected.

So, the total yellow highlighters left after selecting one = 12 -1 = 11

Also, the number of blue highlighter = 6

So, the TOTAL FAVORABLE options to E2 = 6+ 11 = 17

P(E2) =

$\frac{\textrm{Total number of yellow + Blue highlighters}}{\textrm{Total Highlighters}}$ = $\frac{17}{25}$

Hence, the probability that a blue or yellow highlighter is selected given that a yellow highlighter is selected is 17/25.

7 0

3 years ago

Find the volume of the prism

Nimfa-mama [501]

Answer:

V =648 mm^3

Step-by-step explanation:

The volume of a prism is given by

V = l*w*h

V = 6*9* 12

V =648 mm^3

8 0

3 years ago

Which statement should go in the box with the question marks? A) Congress could control trade. B) There was no national court sy

slega [8]

Answer:

C.

Step-by-step explanation:

im not completely sure tho

7 0

3 years ago

Prove that : sinA/1+cosA + 1+cosA/sinA=2cosecA

tekilochka [14]

Step-by-step explanation:

$\frac{sinA}{1+cosA} +\frac{1+cos}{sinA} =2cosec\\\\\\\frac{sin^{2}A+(1+cos)^{2} }{sinA(1+cosA)} \\\\$

$\frac{sin^{2}A+1+cos^{2}+2cos}{sinA(1+cosA)} \\\\$ and we have $sin^{2}+cos^{2} =1$

so $\frac{1+1+2cosA }{sinA(1+cosA)} \\\\$

$\frac{2+2cosA }{sinA(1+cosA)} \\\\$

$\frac{2(1+cosA)}{sinA(1+cosA)} \\\\$

$\frac{2}{sinA}$ we have $\frac{1}{sin}=cosec\\$

Finally $2cosecA$

I really hope this helps coz it took much time

3 0

3 years ago

Pls help plsplsplsplsplsplspspslpssplsplsplspslpslpslsplspsps

Ainat [17]

Answer:

Option A, Option C, Option E

Step-by-step explanation:

The area of a kite can be identified through 1 / 2 of the multiplication of each diagonal. The first diagonal is equivalent to the addition of 50 cm and 10 cm, while the second is of length 20 cm + 20 cm.

$1 / 2 * ( 50 + 10 ) * ( 20 + 20 ),\\1 / 2 * ( 60 ) * ( 40 ),\\( 30 ) * ( 40 ),\\\\Area of Kite = 1200 square cm$

Consider the first option. If we take a look at the bit 2 * ( 1 / 2 * 20 * 50 ) the 2 and 1 /2 cancel each other out, leaving you with 20 * 50 = 1000 . Respectively in the expression 2 * ( 1 / 2 * 20 * 10 ) the 2 and 1 / 2 cancel each other out, leaving you with 20 * 10 = 200;

$1000 + 200 = 1200 square cm,\\Option A - Correct!$

The second option considers the expression 2 * ( 1 / 2 * 20 * 60 ). Again, the 2 and 1 / 2 cancel each other out, leaving you with 20 * 60;

$20 * 60 = 1200 square cm,\\Option B - Correct!$

Option C is a similar version of option a, besides the fact that the 1 / 2 doesn't exist. Thus, Option C is incorrect!

Option D is a similar version of option a as well, but as the 2 doesn't exist, it is incorrect!

This last option, option E is taken as 1 / 2 of the multiplication of the diagonals, and thus is correct!

$1 / 2 * ( 40 * 60 ),\\1 / 2 * ( 2400 ),\\1200 square cm\\\\Correct!$

4 0

3 years ago