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coldgirl [10]
2 years ago
13

Describe how you would estimate the square root of a number that is not a perfect square without using a calculator.

Mathematics
1 answer:
Mariulka [41]2 years ago
5 0
Round of the number to the nearest whole number then multiply it by itself. 
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Line l passes through point (3,−26) and line p is the graph of y−3=−5(x−2) .
uranmaximum [27]

Considering the definition of parallel line, the equation of line l is y= -5x -11.

<h3>Linear equation</h3>

A linear equation o line can be expressed in the form y = mx + b

where

  • x and y are coordinates of a point.
  • m is the slope.
  • b is the ordinate to the origin and represents the coordinate of the point where the line crosses the y axis.

<h3>Parallel line</h3>

Parallel lines are two lines that are always at the same distance from each other.

Two lines are parallel if they have the same slope and different y-intercepts. This is, they have the same value of m and different value of b.

<h3>Equation of parallel line in this case</h3>

In this case, the line is y−3=−5(x−2) Expressed in the form y = mx + b, you get:

y−3=−5x−2×(-5)

y−3=−5x+ 10

y=−5x+ 10 + 3

<u><em>y=  -5x +13</em></u>

where:

  • the slope is -5.
  • the y-intercept is 13.

Two lines are parallel if they have the same slope. So, the parallel line has a slope of -5 and has a form of: y= -5x + b

The line passes through the point (3, -26). Replacing in the expression for parallel line:

-26= -5× 3 + b

-26= -15 + b

-26 + 15 = b

<u><em>-11 = b</em></u>

Finally, the equation of parallel line is y= -5x -11.

Learn more about parallel line:

brainly.com/question/7197064

brainly.com/question/11470863

brainly.com/question/7280013

#SPJ1

3 0
1 year ago
Prove 2^n &gt; n for all n equal to or greater than 1. I mostly need help with how to solve the problem when it is greater than
noname [10]
If n is an integer, you can use induction. First show the inequality holds for n=1. You have 2^1=2>1, which is true.

Now assume this holds in general for n=k, i.e. that 2^k>k. We want to prove the statement then must hold for n=k+1.

Because 2^k>k, you have

2^{k+1}=2\times2^k>2k

and this must be greater than k+1 for the statement to be true, so we require

2k>k+1

for k>1. Well this is obviously true, because solving the inequality gives 3k>1\implies k>\dfrac13. So you're done.

If you n is any real number, you can use derivatives to show that 2^n increases monotonically and faster than n.
7 0
3 years ago
PLEASE HELP
Ad libitum [116K]

Answer:

D. Jessie needs to buy more eggs, flour, butter, and sugar.

Step-by-step explanation:

it is good to have more then none

4 0
2 years ago
Read 2 more answers
With a slope of m = -2 and a point being (5,-2) what’s the Y-intercept?
almond37 [142]

Answer:

c = 8

Step-by-step explanation:

Given the following data;

Slope, m = -2

Points (x, y) = (5, -2)

To find the intercept, c;

Equation of a straight line is given by the formula: y = mx + c

Where;

m is the slope.

x and y are the points

c is the intercept.

Substituting the values in order to find the intercept, we have;

-2 = -2(5) + c

-2 = -10 + c

c = 10 - 2

c = 8

Therefore, the y-intercept is 8.

3 0
3 years ago
3(2x + 11) and (3x + 15)(2)
algol [13]

Answer:

3(2x+11)= 6x+33  and (3x+15)(2) = 6x+30

Step-by-step explanation:

Use distributive property to multiply the outside factor to each factor inside the parenthesis.  

3(2x+11)

(3*2x)+(3*11)

6x+33

3 0
3 years ago
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