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Alona [7]
3 years ago
10

Pls pls help Perform the indicated operations. a) 7a/20b b) 7ab/20 c) 7/20ab

Mathematics
1 answer:
Elina [12.6K]3 years ago
8 0

Answer:

it's a) 7a/20b

Step-by-step explanation:

5( \frac{a + 2}{4b} ) - 2( \frac{a - 1}{10b} ) + 4( \frac{a - 3}{5b} ) \\  \\  \frac{5a + 10 - 2a + 2 + 4a - 12}{20b }  \\  \\  \\  \frac{7a}{20b}

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Let f(x) = x2 − 2x − 3. The secant line through (2, f(2)) and (2 + h, f(2 + h)) for f(x) has slope h + 2. Use this formula to co
Mkey [24]

Answer:

a) slope of secant line = 3

b) slope of tangent line = 2

Step-by-step explanation:

Given:

- The function:

                           f(x) = x^2 -2*x - 3

- The slope for f(x) @ x = 2 is:

                           slope = h + 2

Find:

a) The slope of the secant line through (2, f(2)) and (3, f(3))

b) The slope of the tangent line at x = 2

Solution:

- Since we are given the slope of the line computed via secant method. All we need to do is evaluate the slope given for respective question.

- The slope of secant line between points ( 2 , f(2) ) and ( 3 , f(3) ) is:

                             slope = h + 2

Where,  h is the step size between two points. h = 3 - 2 = 1

                             slope = 1 + 2 = 3

Hence, the slope of the secant is 3.

- The slope of tangent line @ points ( 2 , f(2) ) is:

                             slope = Lim _ h-->0 (h + 2)

Where,  h step size is reduced to infinitesimal small number. Hence, h = 0

                             slope = 0 + 2 = 2

Hence, the slope of the tangent is 2.

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