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Anit [1.1K]
3 years ago
13

If you are this good of a friend that is amazing and if you are not and you are a fake friend do not even comment bc I DON'T LIK

E fake people........NO HATE ALL LOVE!!!!

Mathematics
2 answers:
FrozenT [24]3 years ago
8 0

Answer:

What if I don’t have any best friends and I don’t care enough about my other friends because they don’t care about me? The only friends I have are my friends because they want a human to talk to, not because of my personality. Whenever I talk about my troubles they change the topic. Whenever I want help they make an excuse. Whenever I try to have a constructive debate they start yelling and walk away. Just because you won’t do this for your friend doesn’t men you’re a fake friend. There are many types of fake friends, depending on the victim. I could be a fake friend. You could be a fake friend. Anyone could be. I do believe in toxic people, but even those aren’t “bad”. I am toxic to some people because they’re just too different. You can have a toxic friend who really cares about you, but just isn’t very good for your mental health. Toxic doesn’t equal mean, and fake friends aren’t pure evil. No one is. Like I said to my toxic friend, there is not good or evil, we’re all just people.

Also stop calling people toxic if they’re not just to make them shut up, those words can haunt them for weeks maybe even years like it did to me.

morpeh [17]3 years ago
4 0

Answer:

im not fake ppl deserve real friends not fake

Step-by-step explanation:

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In training for a swim meet, Logan swam 750 meters in \large \frac {1}{3}
worty [1.4K]

Answer:

500

Step-by-step explanation:

7 0
4 years ago
Construct a 90% confidence interval for the true mean using the FPCF. (Round your answers to 4 decimal places.) The 90% confiden
mezya [45]

Answer:

The answer is below

Step-by-step explanation:

Twenty-five blood samples were selected by taking every seventh blood sample from racks holding 187 blood samples from the morning draw at a medical center. The white blood count (WBC) was measured using a Coulter Counter Model S. The mean WBC was 8.636 with a standard deviation of 3.9265. (a) Construct a 90% confidence interval for the true mean using the FPCF. (Round your answers to 4 decimal places.) The 90% confidence interval is from to

Answer:

Given:

Mean (μ) = 8.636, standard deviation (σ) = 3.9265, Confidence (C) = 90% = 0.9, sample size (n) = 25

α = 1 - C = 1 - 0.9 = 0.1

α/2 = 0.1/2 = 0.05

From the normal distribution table, The z score of α/2 (0.05) corresponds to the z score of 0.45 (0.5 - 0.05) which is 1.645

The margin of error (E) is given by:

E=z_{\frac{\alpha}{2} }*\frac{\sigma}{\sqrt{n} }\\ \\E=1.645*\frac{3.9265}{\sqrt{25} }=1.2918

The confidence interval = μ ± E = 8.636 ± 1.2918 = (7.3442, 9.9278)

The 90% confidence interval is from 7.3442 to 9.9278

8 0
4 years ago
Janine wants a necklace 45 beads long 
seraphim [82]
If there are 45 beads, with a ratio of 1:4
Then,
\frac{45}{5}=9
Then if \frac{1}{4}=\frac{9}{x}
Then x=9*4
Therefore, x=36
Meaning, there would be a ratio of 36 beads to 9 beads
4 0
4 years ago
Read 2 more answers
Geometry Help!!!
dem82 [27]
<h3>Answer: Choice A) 24.0</h3>

===============================

Explanation:

Let's say we had a triangle with side lengths a,b,c.

If we know that a = 12.25 and b = 12.25, then the third side c has its length restricted in such a way that

b-a < c < b+a

This is a variation of the triangle inequality theorem.

-------------

So,

b - a < c < b + a

12.25 - 12.25 < c < 12.25 + 12.25

0 < c < 24.5

which means the third side c is between 0 inches and 24.5 inches.

The value of c cannot be 0, and it cannot be 24.5 either.

Among the answer choices given, we see that only 24.0 is the only valid option here. The other two choices are too large.

-------------

Side Note: If your teacher gave you two angles (instead of two sides) to be 12.25 degrees, and wanted the third missing angle of the triangle, then you would be correct in having 12.25+12.25+x = 180 as your first step.

4 0
3 years ago
A motorist left town X at 08 00 for town Y situated 120km away, travelling at a constant speed of v km/hr, so as to arrive at Y
mote1985 [20]
<span>v = 45 km/hr u = 72 km/hr Can't sketch the graph, but can describe it. The Y-axis will be the distance. At the origin it will be 0, and at the highest point it will have the value of 120. The X-axis will be time in minutes. At the origin it will be 0 and at the rightmost point, it will be 160. The graph will consist of 3 line segments. They are 1. A segment from (0,0) to (80,60) 2. A segment from (80,60) to (110,60) 3. A segment from (110,60) to (160,120) The motorist originally intended on driving for 2 2/3 hours to travel 120 km. So divide the distance by the time to get the original intended speed. 120 km / 8/3 = 120 km * 3/8 = 360/8 = 45 km/hr After traveling for 80 minutes (half of the original time allowed), the motorist should be half of the way to the destination, or 120/2 = 60km. Let's verify that. 45 * 4/3 = 180/3 = 60 km. So we have a good cross check that our initial speed was correct. v = 45 km/hr Now having spent 30 minutes fixing the problem, out motorist now has 160-80-30 = 50 minutes available to travel 60 km. So let's divide the distance by time: 60 / 5/6 = 60 * 6/5 = 360/5 = 72 km/hr So the 2nd leg of the trip was at a speed of 72 km/hr</span>
6 0
3 years ago
Read 2 more answers
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