The temperatures of the gases will not be equal as oxygen gas will have a higher temperature than hydrogen gas because it has fewer moles overall.
<h3>Briefing :</h3>
The mechanical behavior of ideal gases is described by the ideal gas law. It has the ability to compute the volume of gases created or absorbed.
This equation is frequently used in chemical equations to convert between volumes and molar quantities.
According to the ideal gas law, there is a relationship between gas pressure, temperature, and volume.
PV = nRT
V is the same for both
So,
T is same for both.
When n increases, T decreases, so since n for hydrogen gas is 1 and n for oxygen gas is 0.5, it follows that oxygen gas will have a higher temperature than hydrogen gas because it has fewer moles overall.
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Work out the number of moles in
100.00 grams of the oxide.
For nitrogen: The atomic mass of N is 14.0067, and we have 36.84 g N:
36.84 g N14.0067 g N/mol N=2.630 mol N
For oxygen: The atomic mass of O is
15.9994, and we have
100.00−36.84=63.16 g O:
63.16 g N 15.9994 g N/mol N=3.948 mol N
Now the ratio 3.958 2.630 is very close to
1.5=32
. So we conclude that the gas has three moles
O to two moles N making the empirical formula
N2O3.
<h2>
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Maybe it's [Acid] and [H+ ions]
Answer:
<u>Volume versus temperature, because they are also directly proportional</u>
Explanation:
The <u>Ideal Gas Equation</u> is :
<u>Evaluating the options</u>
- V ∝ P [Incorrect, because V ∝ 1/P, and graph will be a parabola]
- V ∝ T [Correct, because V ∝ T, and graph is a straight line]
- V ∝ 1/P [Incorrect, because graph is not similar]
- V ∝ 1/T [Incorrect, because V ∝ T]