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Oxana [17]
3 years ago
11

Which phrase change is an endothermic change? (1 point)

Chemistry
1 answer:
Vadim26 [7]3 years ago
5 0
An Endothermic change is a process in which there is absorption of energy.
-Condensation is the transformation from a gas to a liquid. So the water molecules releases energy while condensing, so condensation is exothermic (opposite of endothermic, it's the release of energy)
-Vaporization is the transformation from a liquid to a gas. When you heat water to evaporate it, you're giving energy to the water molecules. And when they absorb this energy, they transform to a gas. Which means that Vaporization is endothermic.
-Deposition is the transformation from gas directly to solid without passing by the liquid phase. Same as the condensation, but the water molecules release even more energy to directly become Solid. So deposition is exothermic.
-Freezing is the transformation from a liquid to a solid. During this phase, water molecules releases energy to its surrounding. So freezing is exothermic.

We can conclude that Vaporization is endothermic, because it's absorbing energy to transform from liquid to gas, while condensation, deposition and freezing are exothermic because they release energy to transform.

Hope this Helps! :)
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Consider the following reaction: SO2Cl2(g)⇌SO2(g)+Cl2(g) A reaction mixture is made containing an initial [SO2Cl2] of 2.2×10−2M
Andrej [43]
The value of equilibrium constant is equal to the quotient of the products raised to its stoichiometric coefficient over the reaction's reactants raised to its respective stoichiometric coeff. The equation is Kc=[SO2][Cl2]/[SO2Cl2]= [1.3*10^-2][1.3*10^-2]/[2.2*10^-2-<span>1.3*10^-2]=0.0188. The final answer is Kc=0.0188.</span>
6 0
3 years ago
How many moles of Al2O3 can be formed from 10.0 g of Al?
Nutka1998 [239]

Answer:

n Al=  10/27( mol)- >n Al2O 3 =5/27(mol)

Explanation:

3 0
2 years ago
State the law of conservation of energy.
LUCKY_DIMON [66]

Answer:

A) The law of conservation of energy states that energy can neither be created nor destroyed.

and

B) Energy can be transferred from one object to another, and it can assume different forms.

6 0
3 years ago
In the combustion of propanol, what is the molar ratio of propanol (ch3ch2ch2oh) to co2? combustion of propanol: 2ch3ch2ch2oh +
maksim [4K]
Propanol molecular formula is C₃H₇OH
the balanced reaction for combustion of propanol is as follows;
2C₃H₇OH + 9O₂ --> 6CO₂  + 8H₂O
Molar ratio of reactants to products can be found out by the stoichiometry.
By looking at the coefficients of reactants and products in the balanced reaction equation, molar ratio can determined.
Therefore the molar ratio of propanol to CO₂ is 2:6, simplified --> 1:3
4 0
3 years ago
t 745 K, the reaction below has an equilibrium constant (Kc) of 5.00 × 102. H2 (g) + I2 (g) ⇌ 2 HI (g) If a mixture of 0.10 mol
spayn [35]

Answer : The concentration of HI (g) at equilibrium is, 0.643 M

Explanation :

The given chemical reaction is:

                        H_2(g)+I_2(g)\rightarrow 2HI(g)

Initial conc.    0.10        0.10      0.50

At eqm.        (0.10-x)  (0.10-x)   (0.50+2x)

As we are given:

K_c=5.00\times 10^2

The expression for equilibrium constant is:

K_c=\frac{[HI]^2}{[H_2][I_2]}

Now put all the given values in this expression, we get:

5.00\times 10^2=\frac{(0.50+2x)^2}{(0.10-x)\times (0.10-x)}

x = 0.0713  and x = 0.134

We are neglecting value of x = 0.134 because the equilibrium concentration can not be more than initial concentration.

Thus, we are taking value of x = 0.0713

The concentration of HI (g) at equilibrium = (0.50+2x) = [0.50+2(0.0713)] = 0.643 M

Thus, the concentration of HI (g) at equilibrium is, 0.643 M

8 0
3 years ago
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