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2 years ago

to find the mass of 3.2 moles of calcium for carbonate which of the following is used to calculate the amount

Chemistry

1 answer:

natka813 [3]2 years ago

6 0

I believe it to be g/mol of Calcium carbonate
because to finde mass...u must have grams(g) as units....
it is the only one that have g as units

as for the first answer the avogadros number gives u the number of atoms in one mole of calcium carbonate....
the second one is based on ... At s.t.p one mole of gas occupies 22.4 dm³⇒to find volume

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Which statement describes heterogeneous mixtures?

Artemon [7]

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2 years ago

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Calculate: A. Mercury has a specific Heat Capacity of 0.14 J/goC. How much heat is needed to raise the thermometer temperature 1

kari74 [83]

Answer:

$\boxed {\boxed {\sf 56 \ Joules}}$

Explanation:

We are given the mass, specific heat, and temperature, so we must use this formula for heat energy.

$q=mc \Delta T$

The mass is 5 grams, the specific heat capacity is 0.14 Joules per gram degree Celsius. Let's find the change in temperature.

ΔT= final temperature - initial temperature
ΔT= 95°C - 15°C = 80°C

We know the variables and can substitute them into the formula.

$m= 5 \ g \\c= 0.14 \ J/ g \ \textdegree C \\\Delta T= 80 \ \textdegree C$

$q= (5 \ g )( 0.14 \ J/ g \ \textdegree C ) ( 80 \ \textdegree C)$

Multiply the first numbers. The grams will cancel.

$q= 0.7 \ J/ \textdegree C(80 \ \textdegree C )$

Multiply again. This time the degrees Celsius cancel.

$q= 56 \ J$

56 Joules of heat are needed.

4 0

2 years ago

Name the first 20 elements on the periodic table

Sergeu [11.5K]

Answer:

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2 years ago

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How many milliliters are in 425 g of bromine if the density of bromine is 3.12 g/cm3

arlik [135]

Answer:

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

$volume = \frac{mass}{density} \\$

From the question

mass = 425

density = 3.12 g/cm³

We have

$volume = \frac{425}{3.12} \\ = 136.2 \: \: {cm}^{3}$

Since cm³ = mL

We have the final answer as

Hope this helps you

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2 years ago

How many grams of iron metal do you expect to be produced when 265 grams of an 84.5 percent by mass iron (II) nitrate solution r

Greeley [361]

The balanced reaction is:

<span>2Al (s) + 3Fe(NO3)2 (aq) = 3Fe (s) + 2Al(NO3)3 (aq)
</span>
We are given the amount of <span>iron (II) nitrate solution with its purity. This will be the starting point of our calculation.

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2 years ago