How many atoms does C₆H₄Cl₂ have?

A child is on a pogo stick. At the top of her jump, her kinetic energy (KE) = 0 J, her gravitational potential energy (GPE) = 10

krek1111 [17]

There would be 0 Potential energy, which eliminates A. There would be Spring energy, which eliminates C. So B and D are your 2 choices. Since the child is not moving just before the jump, there would be 0 Kinetic energy. So D.

7 0

3 years ago

how many liters of a 60% antifreeze solution must be added to 8L of a 10% antifreeze solution to produce a 20% antifreeze soluti

Tasya [4]

Answer: 2Liters

Explanation:

The expression used will be :

$M_1V_1+M_2V_2=M_3V_3$

where,

$M_1$ = concentration of first antifreeze= 60%

$M_2$ = concentration of second antifreeze= 10%

$V_1$ = volume of first antifreeze = x L

$V_2$ = volume of second antifreeze = 8 L

$M_3$ = concentration of final antifreeze solution= 20%

$V_3$ = volume of final antifreeze = (x+8) L

Now put all the given values in the above law, we get the volume of antifreeze added

$60\times x+10\times 8=20\times (x+8)$

$x=2L$

Therefore, the volume of 60% antifreeze solution that must be added is 2L

5 0

3 years ago

The gram molecular mass of co2 is the same as the gram molecular mass of ?

kari74 [83]

The answer is 1. CO. A gram-molecular mass is defined as mass in grams numerically equal to the molecular weight of a substance or the sum of all the atomic masses in its molecular formula. Since CO2 and CO has both carbon and oxygen, the gram-molecular mass does not change. For a compound with carbon and oxygen, the molecular mass comes respectively from 12 (atomic mass of carbon) + (2 × 16) (atomic mass of oxygen), which is 44 g.

3 0

3 years ago

Read 2 more answers

Determine which change of state is being described in this passage

alexandr402 [8]

Explanation:

gas to liquid

correct option

......................

7 0

3 years ago

Read 2 more answers

How many grams of MgCO3 are required to neutralize 200. mL of stomach acid HCl, which is equivalent to 0.0465 MHCl?

tester [92]

<h3>Answer:</h3>

0.392 g

<h3>Explanation:</h3>

We are given the following;

Volume of HCl is 200 mL

Molarity of HCl is 0.0465M

We are required to calculate the mass of MgCO₃ required

<h3>Step 1: Write the balanced equation for the reaction </h3>

The balanced equation for the reaction is;

MgCO₃(s) + 2HCl(aq) → MgCl₂(aq) + CO₂(g) + H₂O(l)

<h3>Step 2: Calculate the moles of HCl</h3>

When given the molarity of a compound and the volume, the number of moles can be calculated by;

Number of moles = Molarity × Volume

Therefore;

Volume of HCl = 0.0465 M × 0.2 L

= 0.0093 moles

<h3>Step 3: Calculating the number of moles of MgCO₃</h3>

From the equation, one mole of MgCO₃ reacts with two moles of HCl

Therefore, the mole ratio of MgCO₃ : HCl is 1 : 2

Hence, moles of MgCO₃ = Moles of HCl ÷ 2

= 0.0093 moles ÷ 2

= 0.00465 moles

To calculate the mass of a compound we need to multiply the molar mass of a compound with the number of moles.

Molar mass of MgCO₃ is 84.314 g/mol

Thus, Mass of MgCO₃ = 0.00465 moles × 84.314 g/mol

= 0.392 g

Therefore, 0.392 g of MgCO₃ are required to neutralize the acid.

3 0

4 years ago