Answer:
t=5.5080( to 3 d.p)
Step-by-step explanation:
From the data given,
n =20
Deviation= 34/20= 1.7
Standard deviation (sd)= 1.3803(√Deviation)
Standard Error = sd/√n
= 1.3803/V20 = 0.3086
Test statistic is:
t = deviation /SE
= 1.7/0.3086 = 5.5080
ndf = 20 - 1 = 19
alpha = 0.01
One Tailed - Right Side Test
From Table, critical value of t =2.5395
Since the calculated value of t = 5.5080 is greater than critical value of t = 2.5395, the difference is significant. Reject null hypothesis.
t score = 5.5080
ndf = 19
One Tail - Right side Test
By Technology, p - value = 0.000
Since p - value is less than alpha , reject null hypothesis.
Conclusion:
From the result obtained it can be concluded that ,the data support the claim that the mean rating assigned to the wine when the cost is described as $90 is greater than the mean rating assigned to the wine when the cost is described as $10.
Hi there..
5/13 t = -9
Solve for T
t = 5/13 * (-9)
t= -177/5
Have a good night !
The probability that the reaction time for this density function is at most 2.5 seconds is equal to 0.9.
<h3>What is a density function?</h3>
A density function can be defined as a type of function which is used to represent the density of a continuous random variable that lies within a specific range.
<h3>How to calculate the probability that reaction time is at most 2.5 seconds?</h3>
P(X ≤ 2.5) = Fx(2.5)
Fx(2.5) = 3/2 - 3/2(2.5)
Fx(2.5) = 3/2 - 3/5
Fx(2.5) = 0.9.
Read more on density function here: brainly.com/question/14448717
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Complete Question:
The reaction time (in seconds) to a certain stimulus is a continuous random variable with pdf:
f(x) = 
What is the probability that reaction time is at most 2.5 seconds?
3.303e+13 that is approximately
