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3 years ago

Do it right plss I need good grades

Mathematics

2 answers:

Alborosie3 years ago

6 0

Answer:its yhe one on the right

Step-by-step explanation:

Harman [31]3 years ago

6 0

Answer:

138 per 6 is the better deal

Step-by-step explan

$23 per g is the unit rate

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This is my last ONE I HAVE TO ANSWER HELP ME

damaskus [11]

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To solve for volume you multiply the measurements of width height and length

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3 years ago

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-10=-15+5x heeeeeeeeeeeeeeeeeeeeeeelp me

Allisa [31]

The answer is -10=-15+5x x = 1

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3 years ago

BRAINLIEST GOING TO THE FIRST ANSWER

Lesechka [4]

Answer:

w + 2.3 > 18

Step-by-step explanation:

MARK ME BRAINLIEST!!!!!!!!!

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3 years ago

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A particle moves on the hyperbola xy=18 for time t≥0 seconds. At a certain instant, y=6 and dydt=8. What is x that this instant?

professor190 [17]

Answer:

The value of x at this instant is 3.

Step-by-step explanation:

Let $x\cdot y = 18$ , we get an additional equation by implicit differentiation:

$x\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0$ (1)

From the first equation we find that:

$x = \frac{18}{y}$ (2)

By applying (2) in (1), we get the resulting expression:

$\frac{18}{y}\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0$ (3)

$y\cdot \frac{dx}{dt}=-\frac{18}{y}\cdot \frac{dy}{dt}$

$\frac{dx}{dt} = -\frac{18}{y^{2}} \cdot \frac{dy}{dt}$

If we know that $y = 6$ and $\frac{dy}{dt} = 8$ , then the first derivative of x in time is:

$\frac{dx}{dt} = -\frac{18}{6^{2}} \cdot (8)$

$\frac{dx}{dt} = -4$

From (1) we determine the value of x at this instant:

$x\cdot \frac{dy}{dt} = -y\cdot \frac{dx}{dt}$

$x = -y\cdot \left(\frac{\frac{dx}{dt} }{\frac{dy}{dt} } \right)$

$x = -6\cdot \left(\frac{-4}{8} \right)$

$x = 3$

The value of x at this instant is 3.

4 0

3 years ago

Work out the length X.

ohaa [14]

Answer:

16.34

Step-by-step explanation:

Is pythagoreons Theron

256 + 11.25 = c squared

267.25 = c squared

16.34 equals approximately c

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3 years ago

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