Answer:
BC + CD = BD
Step-by-step explanation:
The segment addition postulate tells you that when a segment is divided into two parts, the sum of the lengths of the first part of the divided segment and the second part of the divided segment will be equal to the length of the whole segment.
If point C divides segment BD into BC and CD, then the sum of those two segments will match the whole.
(2x/-5x)+x^2
(x(2)/(x(-5))+x^2
(-2/5)+x^2, the x values cancel in numerator and denominator and simplify to -2/5
Answer:
x = - ![\frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D)
Step-by-step explanation:
To find f(g(x)) substitute x = g(x) into f(x), that is
f(g(x))
= f(x + 1)
= 2(x + 1)² ← expand using FOIL
= 2(x² + 2x + 1) ← distribute
= 2x² + 4x + 2
To find g(f(x)) substitute x = f(x) into g(x), that is
g(f(x))
= g(2x²)
= 2x² + 1
----------------------------------------------------------
Equating gives
2x² + 4x + 2 = 2x² + 1 ( subtract 2x² + 1 from both sides )
4x + 1 = 0 ( subtract 1 from both sides )
4x = - 1 ( divide both sides by 4 )
x = - ![\frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D)
Your answer will be X=4c−b<span>
I hope helped ^-^
</span>
Using the linear equation, T = 20x + 31, the total number of computers at the end of 2005 is: C. 191.
<h3>How to Use a Linear Equation?</h3>
A linear equation is expressed as y = mx + b, where x is a function of y, m is the rate of change and b is the y-intercept or starting value.
In the scenario stated, we are given the linear equation for total number of laptop computers at the school after 1997 as, T = 20x + 31.
Rate of change = 20
y-intercept/starting value = 31
x = 2005 - 1997 = 8
To find the total number of laptop computers at Grove High School at the end of 2005 (T), substitute x = 8 into the equation, T = 20x + 31.
T = 20(8) + 31
T = 160 + 31
T = 191 computers.
Thus, total number of computers at the end of 2005 is: C. 191.
Learn more about linear equation on:
brainly.com/question/15602982
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