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Murrr4er [49]
3 years ago
11

A quadrilateral is reflected over the y-axis. Which of the following statements about the coordinates of the image are true?

Mathematics
1 answer:
padilas [110]3 years ago
3 0
Only the x values change
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Please help me with my homework please answer this correctly
sleet_krkn [62]
6 then thousandths=60,000
1 more thousandth then 10,000=11,000
No hundreths=000
3 more tens then 10,000=40,000
And 4 fewer ones than 10,000=9,996
Add that all together and you get 121, 996
5 0
3 years ago
Which angle measures of 45°
ludmilkaskok [199]

Answer:

first

Step-by-step explanation:

half of right angle

5 0
3 years ago
Evaluate (-48)+(-110)+27
Tpy6a [65]

Answer:

131

Step-by-step explanation:

(-48)+(-110)+27

Remember one of the most important math rules

- * - = +

-*+= -

+*+ =+

+*-=-

That been said

We can now perform the operation

-48-110+27= -131

5 0
3 years ago
Statistics Practice Q8
Ghella [55]
The answer is B, at first the sum is 621 and then you divide by 7 to get your median (88), after you add the two #s of 86 and 87 to 621 and divide by 9. Resulting in the median being 88
6 0
3 years ago
Read 2 more answers
Suppose you are asked to take a sample of men and women in order to measure their emotional IQ. The emotional IQ scale that you
yan [13]

Answer:

The 99% confidence interval for the scores of men is (64.406,75.594).

The 99% confidence interval for the scores of women is (73.609,90.391).

Step-by-step explanation:

We have the standard deviations for the sample, which means that the t-distribution will be used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 25 - 1 = 24

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.995. So we have T = 2.797.

For men:

Standard deviation of 10.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.797\frac{10}{\sqrt{25}} = 5.594

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 70 - 5.594 = 64.406

The upper end of the interval is the sample mean added to M. So it is 70 + 5.594 = 75.594

The 99% confidence interval for the scores of men is (64.406,75.594).

For women:

Standard deviation of 15.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.797\frac{15}{\sqrt{25}} = 8.391

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 82 - 8.391 = 73.609

The upper end of the interval is the sample mean added to M. So it is 82 + 8.391 = 90.391

The 99% confidence interval for the scores of women is (73.609,90.391).

4 0
3 years ago
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