Hello!
Answer:
36.225
Step-by-step explanation:
Hope this helps!
X= 5x Y=-6 I just added them together
Answer:
I can help you but I'm not see it clear
Complex zeroes always occurs as conjugates.
For z = a + b i conjugate is: a - b i
Another zero is : 2 + 3 i.
Verification:
2 + 3 i + 3 - 3 i = - b/a
- b = 4, a = 1
( 2 + 3 i ) ( 2 - 3 i ) = c / a
4 - 9 i² = c / a
4 + 9 = c / a
c = 13
( x^4 - 4 x³ + 14 x² - 4 x + 13 ) : ( x² - 4 x + 13 ) = x² + 1
x² + 1 = 0
x² = -1, x = i, x = -i
The zeroes are: - i , i , 2 + 3 i, 2 - 3 i.
Answer:
One another zero of f ( x ) is 2 + 3 i.
The dimension of the box of the greatest volume that can be constructed in this way is 12x12x3 and the volume is 432.
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Let x be the side of the square to remove. Then the volume of the box is:
V(x) = (18 - 2x)² * x = 324x - 72x² + 4x³
To find the maximum volume, differentiate and set it to 0:
V'(x) = 324 - 144x + 12x²
0 = x² - 12x + 27
0 = (x - 9)(x - 3)
x = 3 or 9
When x = 3,
V"(x) =-144+24x
V"(3) =-144+72=-72<0
so volume is maximum at x=3
Therefore the box is 12x12x3 and the volume is 432.
Learn more about dimension on:
brainly.com/question/26740257
