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mrs_skeptik [129]
3 years ago
10

How do I do this problem?

Mathematics
1 answer:
Elenna [48]3 years ago
8 0
Roots can be written as fraction exponents. An exponent of 1/2 means the square root.

(12 x^{4})^{1/2} =  \sqrt{12 x^{4} }  \\  \\ \sqrt{12 x^{4} } =  \sqrt{3*4*x^{2}*x^{2}} = 2x^{2} \sqrt{3}
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24 ÷ v x k when v=2 and k=4
Leya [2.2K]

Answer:

48

Step-by-step explanation:

24 ÷ v x k

24 ÷ 2 x 4    

(Since it's multiplication and division, you just go from left to right in order)

12 x 4

48

5 0
3 years ago
SOMEONE PLEASE HELP ME! I have a few of the explanations but I'm not sure if I need more please suggest some thank you
lesantik [10]

Answer:

For tingle #1

We can find angle C using the triangle sum theorem: the three interior angles of any triangle add up to 180 degrees. Since we know the measures of angles A and B, we can find C.

C=180-(A+B)

C=180-(21.24+27.14)

C=131.62

We cannot find any of the sides. Since there is noting to show us size, there is simply just not enough information; we need at least one side to use the rule of sines and find the other ones. Also, since there is nothing showing us size, each side can have more than one value.  

For triangle #2

In this one, we can find everything and there is one one value for each.

- We can find side c

Since we have a right triangle, we can find side c using the Pythagorean theorem

b^2=a^2+c^2

4^2=2^2+c^2

16=4+c^2

12=c^2

c=\sqrt{12}

c=2\sqrt{3}

- We can find angle C using the cosine trig identity

cos(C)=\frac{adjacent}{hypotenuse}

cos(C)=\frac{2}{4}

C=arccos(\frac{2}{4} )

C=60

- Now we can find angle A using the triangle sum theorem

A=180-(B+C)

A=180-(90+60)

A=30

For triangle #3

Again, we can find everything and there is one one value for each.

- We can find angle A using the triangle sum theorem

A=180-(B+C)

A=180-(90+34.88)

A=55.12

- We can find side a using the tangent trig identity

tan(C)=\frac{opposite-side}{adjacent-side}

tan(34.88)=\frac{7}{a}

a=\frac{7}{tan(34.88)}

a=10.04

- Now we can find side b using the Pythagorean theorem

b^2=a^2+c^2

b^2=10.04^2+7^2

b^2=149.8

b=\sqrt{149.8}

5 0
3 years ago
In an expression<br>(8/9) squared (-81)+3/5dividedby-9/10
Nitella [24]
If you wanted to calculate it, there it is:
(\frac{8}{9})^2 (-81)+\frac{\frac{3}{5}}{\frac{-9}{10}} = \frac{64}{81}*(-81)+\frac{3}{5}*\frac{10}{-9} = -64+\frac{-2}{3}= \\ =-64-\frac{2}{3}=\frac{-192-2}{3}=\frac{-194}{3}
6 0
3 years ago
Read 2 more answers
Solve for x<br> Pls help
Dennis_Churaev [7]

Step-by-step explanation:

collect the like terms 12x+4=9x+8

12x-9x=8-4

3x=4

X=1.333

8 0
3 years ago
Read 2 more answers
If g(x)=4x^2-16 were shifted 5 units to the right and 2 down, what would the new equation be?
Eduardwww [97]
Try this, pls:
When any line on graph is moved to the right, for 'x' must be '-'.
When one is moved down, for 'y' must be '-'.
Finaly: y=4(x-5)²-18.
Answer: A.
4 0
3 years ago
Read 2 more answers
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