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3 years ago

How do I do this problem?

Mathematics

1 answer:

Elenna [48]3 years ago

8 0

Roots can be written as fraction exponents. An exponent of 1/2 means the square root.

$(12 x^{4})^{1/2} = \sqrt{12 x^{4} } \\ \\ \sqrt{12 x^{4} } = \sqrt{3*4*x^{2}*x^{2}} = 2x^{2} \sqrt{3}$

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A pole that is 3.1 m tall casts a shadow that is 1.79 m long. At the same time, a nearby building casts a shadow that is 40.75 m

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Answer:

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Step-by-step explanation:

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The relative frequency table shows a survey on the support for candidate x in an upcoming national election. In this survey, 75

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Answer:

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a) no, because 50% of people who support candidate x are from California, but only 62.5% of all people in the study are from California.

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The total source voltage in the circuit is 6-3i V. What is the voltage at the middle source

Bezzdna [24]

Answer:

<em>The voltage at the middle source is</em> $(2-4\mathbf{i})\ V$

Step-by-step explanation:

<u>Voltage Sources in Series</u>

When two or more voltage sources are connected in series, the total voltage is the sum of the individual voltages of each source.

The figure shown has three voltage sources of values:

$2 + 6\mathbf{i}$

$a + b\mathbf{i}$

$2 - 5\mathbf{i}$

The sum of these voltages is:

$V_t=4+a+(6+b-5)\mathbf{i}$

Operating:

$V_t=4+a+(1+b)\mathbf{i}$

We know the total voltage is $6-3\mathbf{i}$ , thus:

$4+a+(1+b)\mathbf{i}=6-3\mathbf{i}$

Equating the real parts and the imaginary parts independently:

4+a=6

1+b=-3

Solving each equation:

a = 2

b = -4

The voltage at the middle source is $(2-4\mathbf{i})\ V$

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