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tatuchka [14]
3 years ago
12

During August, 10,000 units were produced. The standard quantity of material allowed per unit was 10 pounds at a standard cost o

f $3 per pound. If there was a favorable materials efficiency variance of $18,750 for August, the actual quantity of materials used must be:_______
a. 106,250 pounds.
b. 93,750 pounds.
c. 31,875 pounds.
d. 23,438 pounds
Business
1 answer:
Snowcat [4.5K]3 years ago
7 0

Answer:

actual quantity= 93,750 pounds

Explanation:

<u>To calculate the actual quantity of direct materials, we need to use the following formula:</u>

Direct material quantity variance= (standard quantity - actual quantity)*standard price

18,750= (10,000*10 - actual quantity)*3

18,750= 100,000*3 - 3actual quantity

3actual quantity= 281,250

actual quantity= 281,250/3

actual quantity= 93,750 pounds

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Ans. The current price of the stock is $56.82

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Hi, well, the problem here is that we have different discount rates, in other words the required rate of return for the stock changes several times, therefore we are going to break this problem in 3 parts, or bring to present value all the cash flows in 3 steps. Let´s start with the value of the dividends.

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PV(1)=\frac{D1}{(1+r(1))^{1} } +\frac{D2}{(1+r(1))^{2} } +\frac{D3}{(1+r(1))^{3} }

PV(1)=\frac{3.29}{(1+0.15)^{1} } +\frac{3.48}{(1+0.15)^{2} } +\frac{3.69}{(1+0.15)^{3} }=7.92

Now, for the second part, we have to bring all cash flows to year 3 at r(2)=13% and then bring it to present value at r(1)=15%. This is because we have 2 different discount rates, this is as follows.

PV(2)=(\frac{D4}{(1+r(2))^{1} } +\frac{D5}{(1+r(2))^{2} } +\frac{D6}{(1+r(2))^{3} })*\frac{1}{((1+r(1)^{3} }

PV(2)=(\frac{3.91}{(1+0.13)^{1} } +\frac{4.15}{(1+0.13)^{2} } +\frac{4.40}{(1+0.13)^{3} })*\frac{1}{(1+0.15)^{3} } =6.42

Finally, we need to bring all the future cash flows from year 7 and beyond, notice that we need to use the return rate r(3) to bring everything to year 6, then we have to bring it to year 3 and then to present value, everything as follows.

PV(3)=(\frac{D7}{(r(3)-g)} )*(\frac{1}{(1+r(2))^{3} } )*(\frac{1}{(1+r(1))^{3} } )

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Price=7.92+6.42+42.48=56.82

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