This isn’t even a question it’s just instructions for a question. can you elaborate???
Answer:
By Using the Greedy- Activity- Selection algorithm
Explanation:
The Greedy- Activity- Selection algorithm in this case involves
First finding a maximum size set S1, of compatible activities from S for the first lecture hall.
Then using it again to find a maximum size set S2 of compatible activities from S - S1 for the second hall.
This is repeated till all the activities are assigned.
It requires θ(n2) time in its worse .
Answer:
yes
Explanation:
because the people will be lazy to go and talk to that person instead They will call each other and discuss
Answer:
The answer is "For the stop and wait the value of S and R is equal to 1".
Explanation:
- As we know that, the SR protocol is also known as the automatic repeat request (ARQ), this process allows the sender to sends a series of frames with window size, without waiting for the particular ACK of the recipient including with Go-Back-N ARQ.
- This process is mainly used in the data link layer, which uses the sliding window method for the reliable provisioning of data frames, that's why for the SR protocol the value of S =R and S> 1.
The answer is already given at the end of the question; solely by the magnitude or severity of expected harm
When assessing risks of harm associated with participation in a research study, the probability of harm and the risk of the severity of harm are two distinctive elements of risk that must be considered. In probability of harm, the fact that not all possible harms are equally probable should be considered. How these two elements occur is a crucial factor in determining the level of risk of harm in a study. Given the sensitivity of the information in the case scenario above, the probability that an individual subject could be identified is low while the magnitude of the possible risk of harm is high.
