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sveta [45]
3 years ago
10

Gina deposits $2,000 into each of two savings accounts.

Mathematics
1 answer:
BartSMP [9]3 years ago
4 0

Answer:

<u>Simple interest:</u>

  • $2000*(1 + 3*0.05) = $2300

<u>Compound interest:</u>

  • $2000*(1 + 0.05)^3 = $2315.25

<u>Sum of the balances:</u>

  • $2300 + $2315.25 = $4615.25
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-9 is____ units away from 0 on the number line.
Aloiza [94]

Answer:

My answer would be 9 unit away

Step-by-step explanation:

becuase you can subtract 0 from -9

0 + -9  would equal -9

then 9 - (-9) = 0

so 9 is my answer

sorry if i am wrong

7 0
3 years ago
The nth term of a sequence is 2n-1.
damaskus [11]

Answer: 25, 31 and 37

Step-by-step explanation:

(2n-1)= 19, 21, 23, 25, 27, 29, 31, 33, 35, 37

(3n+1)= 19, 22, 25, 28, 31, 34, 37,

5 0
3 years ago
Simplify the expression. -2/3c -9/5 + 14c + 3/10
Andrew [12]

Answer:

13 \frac{1}{3} c - 1 \frac{1}{2}

Step-by-step explanation:

We want to combine alike terms so

-2/3c+14c & -9/5+3/10

14c-2/3

\frac{14}{1} c -  \frac{2}{3} c

Multiply 14/1 by 3/3 to get the denominators the same

\frac{42}{3} c -  \frac{2}{3} c

Subtract

\frac{40}{3} c

simplify

13 \frac{1}{3} c

now

\frac{3}{10}  -  \frac{9}{5}

Multiply 9/5 by 2/2

\frac{3}{10}  -  \frac{ 18}{10}

Subtract

- \frac{15}{10}

Simplify

- 1 \frac{1}{2}

put both together

13 \frac{1}{3}c  - 1 \frac{1}{2}

Hope this helps! If you have any questions on how I got my answer feel free to ask. Stay safe!

5 0
3 years ago
Read 2 more answers
Two classes have a total of 60 students. The students need to make teams of 8t
Step2247 [10]

Answer:

We have 7 complete teams

Step-by-step explanation:

Here, we have students preparing to make a team of 8 students per team. We now want to know how many complete teams they can make if they are a total of 60;

To get this, we need the multiples of 8;

we have;

8, 16 , 24 , 32, 40 , 48 , 56

So breaking it in 8s, we have;

8 8 8 8 8 8 8

We have 7 8s;

So there would be four left overs

3 0
3 years ago
I really need the answers to these questions so can anybody tell me the answers
loris [4]
It's really important that you aim to understand how to do these problems yourself, rather than "pay" others to do them for you.  Why not ask for "directions" or "guidance," instead of for "answers?"

This is a tricky question because it's not required that you have the full 12 beads on the string in every case.  You could, for example, have 6 beads, 2 of which would be red, making the ratio of red beads 2 to 6, or 1 to 3.  

What about 3 red beads in 9?
What about 1 red bead in 3?
Do these "answers" satisfy the requirement that the ratio of red beads to all beads is 1:3?
5 0
3 years ago
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