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2 years ago

Choose whether the probability is mutually exclusive or not

Mathematics

1 answer:

Semmy [17]2 years ago

4 0

9514 1404 393

Answer:

mutually exclusive

Step-by-step explanation:

The formula of interest is ...

P(A or B) = P(A) + P(B) - P(A and B)

Filling in the given values, we have ...

9/10 = 2/5 + 1/2 - P(A and B)

Solving for P(A and B), we get ...

P(A and B) = 2/5 +1/2 -9/10 = 4/10 +5/10 -9/10

P(A and B) = 0

Events are mutually exclusive when <em>they can never happen at the same time</em>. That is, P(A and B) = 0.

The events A and B are mutually exclusive.

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E=6c^2-2c-1<br> F=-4c^2+7c+5<br> E+F=

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E + F = 2c^2 + 5c + 4

Step-by-step explanation:

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2 years ago

Which of the two solids below are similar ?

Pachacha [2.7K]

Answer: I and II.

Step-by-step explanation:

By definition, two solids are similar if their corresponding sides are in the same ratio.

Knowing this, let's find which solids are similar:

Corresponding sides ratio of solids I and II:

$\frac{3}{2}=\frac{2}{\frac{4}{3}}=\frac{5}{\frac{10}{3}}$

$\frac{3}{2}=\frac{3}{2}=\frac{3}{2}$

Corresponding sides ratio of solids I and III:

$\frac{3}{\frac{9}{2}}=\frac{2}{3}=\frac{5}{8}$

$\frac{2}{3}=\frac{2}{3}=\frac{5}{8}$

Corresponding sides ratio of solids II and III:

$\frac{2}{\frac{9}{2}}=\frac{\frac{4}{3}}{3}}=\frac{\frac{10}{3}}{8}}$

$\frac{4}{9}=\frac{4}{9}=\frac{5}{12}$

You can observe that the solids I and II are similar.

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