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3 years ago

Surface of cylinders formula

Mathematics

1 answer:

vagabundo [1.1K]3 years ago

7 0

Answer:

V=Bh or V=πr2h

Step-by-step explanation:

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There are 52 titled chapters in this book. Is there a sure possibility that some chapters start with the same a) letter b) word?

kipiarov [429]

Answer:

there is sure probability to that some chapters will start with the same letter. There is no sure probability that some chapters will start with same word

Step-by-step explanation:

there are 26 letters in the English alphabet

probability that one letter will start a chapter

is 1/26.

Number of pages=52

1/26×52=2

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3 years ago

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The graph represents the distance in miles, y: that Car A travels in x minutes. The function y x represents the distance, y; tha

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3 years ago

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Allisa [31]

Answer:

23. x= -2/5 x= -5

24. x= 3/4 x= -1/6

25. x= 7/3. x= -5/4

26. x= 3 x= -2/3

27. x= 1. x= -2/7

28. x= 9/4. x= -1/3

29. x= 2/5 x= 1/3

30. x= 2/3 x= 1/2

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3 years ago

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aivan3 [116]

Answer:

y is going back by 3's x is going back one

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3 years ago

Newton's law of cooling is:

Mnenie [13.5K]

Answer:

$t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr$

So it would takes approximately 6.9 hours to reach 32 F.

Step-by-step explanation:

For this case we have the following differential equationÑ

$\frac{du}{dt}= -k (u-T)$

We can reorder the expression like this:

$\frac{du}{u-T} = -k dt$

We can use the substitution $w = u-T$ and $dw =du$ so then we have:

$\frac{dw}{w} =-k dt$

IF we integrate both sides we got:

$ln |w| = -kt +C$

If we apply exponential in both sides we got:

$w = e^{-kt} *e^c$

And if we replace w = u-T we got:

$u(t)= T + C_1 e^{-kt}$

We can also express the solution in the following terms:

$u(t) = (T_i -T_{amb}) e^{kt} +T_{amb}$

For this case we know that $k =-0.15 hr$ since w ehave a cooloing, $T_{i}= 70 F, T_{amb}=11F$ , we have this model:

$u(t) = (70-11) e^{-0.15t} +11$

And if we want that the temperature would be 32F we can solve for t like this:

$32 = 59 e^{-0.15 t} +11$

$21=59 e^{-0.15 t}$

$\frac{21}{59} = e^{-0.15 t}$

If we apply natural logs on both sides we got:

$ln (\frac{21}{59}) =-0.15 t$

$t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr$

So it would takes approximately 6.9 hours to reach 32 F.

7 0

3 years ago

Surface of cylinders formula​

Surface of cylinders formula