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Ainat [17]
3 years ago
9

A student was asked to refine a model comparing DNA and RNA. The structures were compared originally, but the teacher asked

Biology
1 answer:
enyata [817]3 years ago
4 0

Answer:

B) DNA and RNA both carry genetic information that encoded for proteins.

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Knowing what we know about the link between genetics, environment and intelligence, what would be your expectations if you were
Vesnalui [34]

Answer:

I would expect them to perform similar.

Explanation:

Studies suggest that intelligence has a genetic component and can, in part, be passed from parent to child - but not only that. There are outer components that contribute to the formation of intelligent individuals. Better nutrition and more access to education would be possible explanations for the progressive increase in intelligence test scores over time.

Homozygous twins are those that are mainly characterized by similarity between individuals. These twins are formed from the same zygote, ie after the fertilization process. Because of this characteristic, they have the same genetic heritage and are therefore considered identical.

As the homozygous twins in their classroom have the same genetic heritage and attend the same environment, we can conclude that their intelligence is influenced by the same factors. For this reason, a teacher who taught these two brothers might have expectations that they would perform similarly in the classroom.

6 0
4 years ago
Dew point Definition.
Thepotemich [5.8K]
The atmospheric temperature (varying according to pressure and humidity) below which water droplets begin to condense and dew can form.
4 0
3 years ago
2. Members of this kingdom secrete enzymes into their food then absorb the digested matter
Fudgin [204]

Answer:

Fungi

Explanation:

Fungi are an example of saprotrophs i.e. organisms who live and feed on dead organic matter. Saprotrophic nutrition is described as chemoheterotrophic extracellular digestion. It involves the extracellular release of digestive enzymes on the organic matter. The enzymes break down the organic matter into a simpler form, which is then absorbed by the fungus.

4 0
3 years ago
The functional anatomy of basal ganglia disorders Author links open overlay panelRoger L.AlbinAnne B.Young John B.Penney
Roman55 [17]

A diverse range of clinical syndromes with a shared anatomic location inside the basal ganglia are known as basal ganglia disorders.

<h3>What is functional anatomy of basal ganglia disorders model ?</h3>

A model in which particular types of basal ganglia disorders are associated with changes in the function of subpopulations of striatal projection neurons. This model aims to explain the variety of clinical manifestations associated with insults to various parts of the basal ganglia.

  • This model is based on an analysis of post-mortem anatomical and neurochemical data from humans and experimental animals. The excess of aberrant movements that characterise hyperkinetic diseases are thought to be caused by a specific dysfunction of striatal neurons that project to the lateral globus pallidus.

Learn more about Basal ganglia disorders here:

brainly.com/question/14448182

#SPJ4

4 0
1 year ago
Genes for body color (B black dominant to b yellow) and wing shape (C straight dominant to c curved) are located on the same chr
xxMikexx [17]

Answer:

Map distance = Genetic distance, GD = 3.9 MU ≅ 4 MU

Explanation:

The more separated two genes are, the more chances of recombination there will be.  The closer they are, the fewer chances of recombination there will be. Two genes that are very close will have a few recombination events and are strongly bounded.    

To analyze the recombination frequency, we have to know that:

  • 1% of recombination = 1 map unit = 1centi Morgan = 1,000,000 base pairs.
  • And that the maximum recombination frequency is always 50%.  

The map unit is the distance between the pair of genes for which every 100 meiotic products one of them results in a recombinant one.  

Knowing that the genes are linked, we can calculate genetic distances between them. First, we need to identify the genotypes of the parental gametes with the ones of the recombinants. We can recognize the parental gametes in the descendants because their phenotypes are the most frequent, while the recombinants are the less frequent. So:

Parentals:

  • black, curved 337
  • yellow, straight 364

Recombinants:

  • Black, straight 17
  • yellow, curved 12

To calculate the recombination frequency we will make use of the next formula: P = Recombinant number / Total of individuals.

P = Recombinant number / Total of individuals.  

P = 17 + 12 / 337 + 364 + 17 + 12

P = 29 / 730

P = 0.039

The genetic distance (GD) will result from multiplying that recombination frequency (P) by 100 and expressing it in map units (MU).

GD = P x 100

GD = 0.039 x 100

GD = 3.9 MU ≅ 4 MU

3 0
3 years ago
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