Answer:
C
Explanation:
C) adding a catalyst to the reaction.
Complete question:
The decomposition of SO2Cl2 is first order in SO2Cl2 and has a rate constant of 1.44×10⁻⁴ s⁻¹ at a certain temperature.
If the initial concentration of SO2Cl2 is 0.125 M , what is the concentration of SO2Cl2 after 210 s ?
Answer:
After 210 s the concentration of SO2Cl2 will be 0.121 M
Explanation:
![ln\frac{[A_t]}{[A_0]} =-kt](https://tex.z-dn.net/?f=ln%5Cfrac%7B%5BA_t%5D%7D%7B%5BA_0%5D%7D%20%3D-kt)
where;
At is the concentration of A at a time t
A₀ is the initial concentration of A
k is rate constant = 1.44×10⁻⁴ s⁻¹
t is time
ln(At/A₀) = -( 1.44×10⁻⁴)t
ln(At/0.125) = -( 1.44×10⁻⁴)210
ln(At/0.125) = -0.03024

At/0.125 = 0.9702
At = 0.125*0.9702
At = 0.121 M
Therefore, after 210 s the concentration of SO2Cl2 will be 0.121 M
count the elements in eqn MgI2 + Br2 -> MgBr2 + I2
1 Mg, 2I, 2Br on the left n
1 Mg, 2I, 2Br on the right
they are equal so the eqn is balanced
<span>Biological specimens have been preserved in alcohol and formalin for many years.This could damage the specimen and change the colour of the fluid.Engineered fluids are now used as a substitute for formalin as it is a more sustainable medium..Novec fluids which are low in toxicity are also used.</span>
Answer:
grams of solute = 31.5 g
Explanation:
Given data:
Grams of solute = ?
%m/v = 3%
Volume = 1050 mL
Solution:
grams of solute = 3 g of NH₄Cl / 100 mL × 1050 mL
grams of solute = 0.03 g × 1050
grams of solute = 31.5 g