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Anuta_ua [19.1K]
3 years ago
9

Which of the following has the highest concentration? *

Chemistry
1 answer:
e-lub [12.9K]3 years ago
5 0
Letter B

#carryonlearning
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The activiation energy required for a chemical reaction can be decreased by.
balandron [24]

Answer:

C

Explanation:

C) adding a catalyst to the reaction.

4 0
3 years ago
If the initial concentration of SO2Cl2 is 0.125 M , what is the concentration of SO2Cl2 after 210 s ?
andre [41]

Complete question:

The decomposition of SO2Cl2 is first order in SO2Cl2 and has a rate constant of 1.44×10⁻⁴ s⁻¹ at a certain temperature.

If the initial concentration of SO2Cl2 is 0.125 M , what is the concentration of SO2Cl2 after 210 s ?

Answer:

After 210 s the concentration of SO2Cl2  will be 0.121 M

Explanation:

ln\frac{[A_t]}{[A_0]} =-kt

where;

At is the concentration of A at a time t

A₀ is the initial concentration of A

k is rate constant = 1.44×10⁻⁴ s⁻¹

t is time

ln(At/A₀) = -( 1.44×10⁻⁴)t

ln(At/0.125) =  -( 1.44×10⁻⁴)210

ln(At/0.125) = -0.03024

\frac{A_t}{0.125} = e^{-0.03024

At/0.125 = 0.9702

At = 0.125*0.9702

At = 0.121 M

Therefore, after 210 s the concentration of SO2Cl2  will be 0.121 M

6 0
3 years ago
Is the following chemical equation balanced? MgI 2 + Br 2 MgBr 2 + I 2
kirill [66]

count the elements in eqn  MgI2 + Br2 ->  MgBr2 + I2

1 Mg, 2I, 2Br on the left n

1 Mg, 2I, 2Br on the right

they are equal so the eqn is balanced

4 0
3 years ago
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Which compound can be used to preserve biological specimens?
Ksju [112]
<span>Biological specimens have been preserved in alcohol and formalin for many years.This could damage the specimen and change the colour of the fluid.Engineered fluids are now used as a substitute for formalin as it is a more sustainable medium..Novec fluids which are low in toxicity are also used.</span>
7 0
3 years ago
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Grams needed to prepare the solution
erastovalidia [21]

Answer:

grams of solute = 31.5 g

Explanation:

Given data:

Grams of solute = ?

%m/v  = 3%

Volume = 1050 mL

Solution:

grams of solute = 3 g of NH₄Cl / 100 mL × 1050 mL

grams of solute = 0.03 g × 1050  

grams of solute = 31.5 g

8 0
3 years ago
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