Answer:
o
Explanation:
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Answer by YourHope:
Hi! :)
Answers:
A catalyst is a substance that changes the rate of the reaction, and is not consumed in the reaction!
A solution is a uniform mixture of molecules or ions of one substance in another!
A solute is the substance dissolved in a solution!
A solution is the substance that does the dissolving in a solution!
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The balanced equation for the above reaction is as follows
C₆H₁₂O₆(s) + 6O₂(g) --> 6H₂O(g) + 6CO₂<span>(g)
the limiting reactant in the equation is glucose as the whole amount of glucose is used up in the reaction.
the amount of </span>C₆H₁₂O₆ used up - 13.2 g
the number of moles reacted - 13.2 g/ 180 g/mol = 0.073 mol
stoichiometry of glucose to CO₂ - 1:6
then number of CO₂ moles are - 0.073 mol x 6 = 0.44 mol
As mentioned this reaction takes place at standard temperature and pressure conditions,
At STP 1 mol of any gas occupies 22.4 L
Therefore 0.44 mol of CO₂ occupies 22.4 L/mol x 0.44 mol = 9.8 rounded off - 10.0 L
Answer is B) 10.0 L CO₂
Answer:
0.25 M
Explanation:
The first step is to determine how many moles of glucose there are, which means first finding out the molar mass of glucose. Carbon has a molar mass of about 12, hydrogen 1, and oxygen 16, so the total molar mass of glucose is about 6(12)+12(1)+6(16)=180 grams. This means that 90 grams is half a mole. Half a mole of substance divided by two liters of solution is (1/2)/2=1/4, or a molarity of 0.25. Hope this helps!
As we know that,
1 mm Hg = 1 torr
So,
745 mm Hg = X
X = (745 mm Hg × 1 torr) ÷ 1 mm Hg
X = 745 torr
Also,
1 mm Hg = 133.325 Pa
So,
745 mm Hg = X
X = (745 mm Hg × 133.325 Pa) ÷ 1 mm Hg
X = 99327 Pa
Result:
Option-A (745 torr) is the correct answer.
