Hydroboration-oxidation is a reaction which follow anti markonikov orientation.
The stereochemistry of hydroboration-oxidation follows syn-adition being a stereospecific reaction. That means that boron and hydrogen are added from the same side. Then, when the oxidation occurs, the boron is replaced by an hydroxyl having the same geometric position.
The empirical formula of the alcohol is C₄H₄O
To solve the question given above, we'll begin by calculating the percentage of oxygen in the compound. This can be obtained as follow:
Carbon (C) = 70.57 %
Hydrogen (H) = 5.935 %
<h3>Oxygen (O) =? </h3>
O = 100 – (C + H)
O = 100 – (70.57 + 5.935)
O = 100 – 76.505
<h3>O = 23.495%</h3>
Finally, we shall determine the empirical formula of the compound. This can be obtained as follow:
Carbon (C) = 70.57 %
Hydrogen (H) = 5.935 %
Oxygen (O) = 23.495%
<h3>Empirical formula =?</h3>
Divide by their molar mass
C = 70.57 / 12 = 5.881
H = 5.935 /1 = 5.935
O = 23.495 / 16 = 1.468
Divide by the smallest
C = 5.881 / 1.468 = 4
H = 5.935 / 1.468 = 4
O = 1.468 / 1.468 = 1
Therefore, the empirical formula of the alcohol is C₄H₄O
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Answer:
Models 2 and 3
Explanation:
Just makes sense. Hope this helps.
