All categories

3 years ago

Find each product 64x100

Chemistry

2 answers:

elixir [45]3 years ago

8 0

Answer:

6400

Explanation:

fenix001 [56]3 years ago

7 0

6400

Explanation:
Do 64 times 1= 64
Then add on the zeros
6400

You might be interested in

Given the reaction 2NO2 1/202 N2O5, what is the relationship between the rates of formation of N,0, and disappearance of the two

daser333 [38]

Answer:

$r=\frac{r(NO_{2})}{2} =\frac{r(O_{2})}{1/2}=\frac{r(N_{2}O_{5})}{1}$

Explanation:

Let us consider the reaction:

2 NO₂ + 1/2 O₂ ⇄ N₂O₅

The rate of formation of a substance is equal to the change in concentration of the product divided the change in time:

$r(N_{2}O_{5})=\frac{\Delta [N_{2}O_{5}] }{\Delta t}$

The rate of disappearance of a reactant is equal to to the change in concentration of the reactant divided the change in time, with a negative sign so that the rate is always a positive variable.

$r(NO_{2})=-\frac{\Delta[NO_{2}] }{\Delta t}$

$r(O_{2})=-\frac{\Delta[O_{2}] }{\Delta t}$

The rate of the reaction is equal to the rate of any substance divided its stoichiometric coefficient. In this way, we can relate these expressions:

$r=\frac{r(NO_{2})}{2} =\frac{r(O_{2})}{1/2}=\frac{r(N_{2}O_{5})}{1}$

8 0

3 years ago

Which of the following are observations? The candle floats. The tires are flat. The dog is barking. The tire is flat because of

Liula [17]

Everything but "<span>The tire is flat because of a decrease in temperature" is an observation.</span>

6 0

3 years ago

Read 2 more answers

I’ll mark you brainlist

kaheart [24]

It’s B the high mass stars

7 0

3 years ago

Read 2 more answers

How many grams of sodium metal must be introduced to water to produce 3.3 grams of hydrogen gas?

Cloud [144]

Answer:

The mass of sodium metal that must be introduced to water to produce 3.3 grams of hydrogen gas, H₂, is approximately 18.82 grams of sodium metal

Explanation:

The given mass of hydrogen gas produced = 3.3 grams

The molar mass of hydrogen gas, H₂ = 2.016 g/mol

The number of moles of hydrogen gas in 3.3 grams of H₂, 'n', is given as follows;

n = Mass/(Molar mass)

n = 3.3 g/(2.016 g/mol) = 1.63690476 moles of H₂

The reaction of sodium and water can be written as follows;

2Na + 2H₂O → 2NaOH + H₂ (g)

2 moles of sodium produces 1 mole of hydrogen gas, H₂

Therefore;

1.63690476/2 moles of sodium will produce 1.63690476 moles of hydrogen gas, H₂

The molar mass of sodium, Na ≈ 22.989 g/mol

The mass of 1.63690476/2 moles of sodium, 'm', is given as follows;

m = 1.63690476/2 moles × 22.989 g/mol ≈ 18.8154018 grams ≈ 18.82 grams

The mass of sodium that will produce 3.3 grams of hydrogen, m ≈ 18.82 grams of sodium metal.

8 0

3 years ago

A nonvolatile solute is dissolved in benzene so that it has a mole fraction of 0.139. What is the vapor pressure of the solution

lapo4ka [179]

Answer:

The vapor pressure of the solution is 3.69 torr

Explanation:

Step 1: Data given

Mole fraction of benzene in the solution = 0.139

P° of benzene is 26.5 torr

Step 2: Calculate the vapor pressure of the solution

Psolution = Xbenzene * P°benzene

⇒with Psolution = the vapor pressure of the solution

⇒with Xbenzene = the mole fraction of benzene = 0.139

⇒with P°benzene = the vapor pressure of pure benzene = 26.5 torr

Psolution = 0.139 * 26.5 torr

Psolution = 3.69 torr

The vapor pressure of the solution is 3.69 torr

7 0

3 years ago