Answer:
Step-by-step explanation:
The given line passes through: (0,-3), (2,0), and (4,3).
We first of all find the slope using 
Using 
we find the slope to be
The equation is given by 
, where 
is the slope and c=-3 is the y-intercept.
Therefore the equation is
Answer: y = 4x/3 - 5/2
Step-by-step explanation:
The equation of a straight line can be represented in the slope intercept form as
y = mx + c
Where
c represents the y intercept
m = slope = (y2 - y1)/(x2 - x1)
The given line, L1 passes through A(6, - 7) and B(- 6, 2). The slope of line L1 is
m = (2 - - 7)/(- 6 - 6) = 9/ -12 = - 3/4
If two lines are perpendicular, it means that the slope of one line is the negative reciprocal of the slope of the other line.
Therefore, the slope of line L2 passing through the midpoint, M is 4/3
The formula determining the midpoint of a line is expressed as
[(x1 + x2)/2 , (y1 + y2)/2]
Midpoint, M = [(6 + -6)/2 , (- 7 + 2)/2]
= (0, - 5/2]
This means that the y intercept of line L2 is - 5/2
The equation of L2 becomes
y = 4x/3 - 5/2
Answer:
yeah
Step-by-step explanation:
-- He must have at least one of each color in the case, so the first 3 of the 5 marbles in the case are blue-green-black.
Now the rest of the collection consists of
4 blue
4 green
2 black
and there's space for 2 more marbles in the case.
So the question really asks: "In how many ways can 2 marbles
be selected from 4 blue ones, 4 green ones, and 2 black ones ?"
-- Well, there are 10 marbles all together.
So the first one chosen can be any one of the 10,
and for each of those,
the second one can be any one of the remaining 9 .
Total number of ways to pick 2 out of the 10 = (10 x 9) = 90 ways.
-- BUT ... there are not nearly that many different combinations
to wind up with in the case.
The first of the two picks can be any one of the 3 colors,
and for each of those,
the second pick can also be any one of the 3 colors.
So there are actually only 9 distinguishable ways (ways that
you can tell apart) to pick the last two marbles.
