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Gre4nikov [31]
3 years ago
15

Please help!!! the graph of F(x), shown below, has the same shape as the graph of G(x)=x^3, but it shifted down 1 unit. what is

its equation

Mathematics
2 answers:
balandron [24]3 years ago
7 0

Answer:

F(x) = x^{3)-1[

Step-by-step explanation:

In the graph is given a curve which has the same shape as the parent curve

G(x) = x^{3)}

but shifted 1 unit down.

Since there is no horizontal change x will remain as it is.

Since there is a vertical shift down of 1 unit,

we have F(x) = G(x)-1

This will only shift vertically down one unit without affecting horizontally.

Hence the relation is

F(x) = x^{3)-1

Option C is correct

rusak2 [61]3 years ago
6 0
One unit down means a change in the y-axis. The graph one unit above shows no y-intercept in the equation because the intercept is 0.
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22. Determine the value of c so that the line
tiny-mole [99]

Answer:

If the lines BC and DE are parallel, the value of c is c=-2

Step-by-step explanation:

We are given line segment BC with end points B(2, 2) and C(9,6) and line segment DE with endpoints  D(c, -7) and E(5, -3).

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x_1=2, y_1=2, x_2=9, y_2=6 \ for \ line \ BC \ and \\\x_1=c, y_1=-7, x_2=5, y_2=-3 \ for \ line \ DE \

Putting values and finding c

\frac{6-2}{9-2}=\frac{-3-(-7)}{5-c}\\ \frac{4}{7}=\frac{-3+7}{5-c} \\ \frac{4}{7}=\frac{4}{5-c} \\Cross \ multiply:\\4(5-c)=4*7\\20-4c=28\\-4c=28-20\\-4c=8\\c=\frac{8}{-4}\\c=-2

So, If the lines BC and DE are parallel, the value of c is c=-2

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