Question

The perimeter of a rectangular building is 346 meters.It is 132 meters long.How wide is it

Answer 1

2L + 2w = 112 ---> L + w = 56 ---> w = 56- L


Area = L*w = L(56-L) = 735

56L - L^2 = 735

0 = L^2 - 56L + 735

0 = (L - 21)(L - 35)

THe dimensions of the rectangle are 35 x 21

Answer 2

Answer:  41 meters

===========================================================

w = unknown width

We have two copies of w, since we have two parallel width portions, along with two copies of 132 being added to get the perimeter of the rectangle.

perimeter = sum of all sides

p = 132+132+w+w

p = 2w+264

Set this equal to the given perimeter of 346 and solve for w

2w+264 = 346

2w = 346-264

2w = 82

w = 82/2

w = 41

The width of the building is 41 meters