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myrzilka [38]
3 years ago
11

Yesterday movie theaters sold 261 bags of popcorn a large bag of popcorn cost three dollars a small bag of popcorn cost one doll

ar in all the movie theater made $443 from popcorn sales right and solve a system of equations to find how many bags of each size of popcorn were sold
Mathematics
1 answer:
kherson [118]3 years ago
7 0
Kannaoakaksmsamammamsmma 66
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What is the probability that more than twelve loads occur during a 4-year period? (Round your answer to three decimal places.)
Nataly_w [17]

Answer:

Given that an article suggests

that a Poisson process can be used to represent the occurrence of

structural loads over time. Suppose the mean time between occurrences of

loads is 0.4 year. a). How many loads can be expected to occur during a 4-year period? b). What is the probability that more than 11 loads occur during a

4-year period? c). How long must a time period be so that the probability of no loads

occurring during that period is at most 0.3?Part A:The number of loads that can be expected to occur during a 4-year period is given by:Part B:The expected value of the number of loads to occur during the 4-year period is 10 loads.This means that the mean is 10.The probability of a poisson distribution is given by where: k = 0, 1, 2, . . ., 11 and λ = 10.The probability that more than 11 loads occur during a

4-year period is given by:1 - [P(k = 0) + P(k = 1) + P(k = 2) + . . . + P(k = 11)]= 1 - [0.000045 + 0.000454 + 0.002270 + 0.007567 + 0.018917 + 0.037833 + 0.063055 + 0.090079 + 0.112599 + 0.125110+ 0.125110 + 0.113736]= 1 - 0.571665 = 0.428335 Therefore, the probability that more than eleven loads occur during a 4-year period is 0.4283Part C:The time period that must be so that the probability of no loads occurring during that period is at most 0.3 is obtained from the equation:Therefore, the time period that must be so that the probability of no loads

occurring during that period is at most 0.3 is given by: 3.3 years

Step-by-step explanation:

8 0
4 years ago
What is the answer to 10lb 6oz- 7lb 11oz
sweet-ann [11.9K]
1 lb = 16 oz
Translating the unit into oz gives us
166oz - 123oz = 43oz or 2lb 11oz

3 0
3 years ago
PLEASE HELP THIS IS THE FINAL SUBMISSION
choli [55]

2) Answer:  I = $ 10.56

Equation:

I = Prt

Calculation:

First, converting R percent to r a decimal

r = R/100 = 0.6%/100 = 0.006 per year,

then, solving our equation

I = 440 × 0.006 × 4 = 10.56

I = $ 10.56

The simple interest accumulated

on a principal of $ 440.00

at a rate of 0.6% per year

for 4 years is $ 10.56.

4) Answer: I = $ 0.63

Equation:

I = Prt

Calculation:

First, converting R percent to r a decimal

r = R/100 = 0.7%/100 = 0.007 per year,

putting time into years for simplicity,

3 months ÷ 12 months/year = 0.25 years,

then, solving our equation

I = 360 × 0.007 × 0.25 = 0.63

I = $ 0.63

The simple interest accumulated

on a principal of $ 360.00

at a rate of 0.7% per year

for 0.25 years (3 months) is $ 0.63.

8) Answer: I = $ 990.00

Equation:

I = Prt

Calculation:

First, converting R percent to r a decimal

r = R/100 = 9%/100 = 0.09 per year,

then, solving our equation

I = 1000 × 0.09 × 11 = 990

I = $ 990.00

The simple interest accumulated

on a principal of $ 1,000.00

at a rate of 9% per year

for 11 years is $ 990.00.

7 0
3 years ago
Read 2 more answers
here is a data set 36,48,67,91 what is the mean median mode range plz help exams tommorow stuck on stupid
NemiM [27]
Range: your highest and lowest number and subtract........91-36 = 55
Mode: is the number that shows up the Most Often..... you don't have one in this.
Median: put all your numbers from least to greatest and cross of one number at a time at each end if you come to 2 numbers in the middle add them up and divide them by 2....... 48+67=115...115/ 2 =57.5
Mean; Add all the numbers up and divide them by how many numbers are there.....36+48+67+91=242...242/ 4 =60.5
5 0
4 years ago
Two times a number is equal to six less than times the number. What is the number ?
son4ous [18]
2x= x-6
X=-6
That is the answer
6 0
4 years ago
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