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hram777 [196]
3 years ago
6

How many ways are there to place 5 basketball players on the court if you must place 2 guards, 2 forwards and a center, from a t

eam of 12, consisting of 4 guards, 5 forwards and 3 centers?
Mathematics
1 answer:
Alex3 years ago
3 0
You can have 2 teams of the following 12 players. The first team out of the 12 will have 2 guards, 2 forwards and a center. The second team will have 2 guards, 2 forwards and a center as well with a remaining of 2 players left
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What is m∠LQK ?<br><br> Enter your answer in the box.
Lady_Fox [76]
∠LQK+∠GQL=90º
Therefore:
(4n-15)+(3n)=90
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Answer: ∠LQK=45º
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You and a friend are playing a game of chance. Every time you roll a 1 or 2 you are successful, and your friend will pay you $1.
LUCKY_DIMON [66]

At the end of the game you owned 13 cents if 71% of your rolls are successful and 29% of your rolls are unsuccessful option first is correct.

<h3>What is probability?</h3>

It is defined as the ratio of the number of favourable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.

We have:

Every time you roll a 1 or 2 you are successful, and your friend will pay you $1. Every time you roll a 3, 4, 5 or 6, you must pay your friend $2.

71% of your rolls are successful:

= 1×0.71

= $0.71 (won)

29% of your rolls are unsuccessful

= 2×2.9

= $0.58 (lose)

The amount owned = 0.71 - 0.58 = $0.13 = 13 cents

Thus, at the end of the game you owned 13 cents if 71% of your rolls are successful and 29% of your rolls are unsuccessful option first is correct.

Learn more about the probability here:

brainly.com/question/11234923

#SPJ1

6 0
2 years ago
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