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UkoKoshka [18]
2 years ago
11

Find the greatest common factor of the monomials. 20x², 36x =

Mathematics
2 answers:
Delvig [45]2 years ago
6 0

Simplifying

-20x2 = 36x

Solving

-20x2 = 36x

Solving for variable 'x'.

Reorder the terms:

-36x + -20x2 = 36x + -36x

Combine like terms: 36x + -36x = 0

-36x + -20x2 = 0

Factor out the Greatest Common Factor (GCF), '-4x'.

-4x(9 + 5x) = 0

Ignore the factor -4. ._.

Goshia [24]2 years ago
3 0

Answer:

i think its -4

Step-by-step explanation:

Simplifying

-20x2 = 36x

Solving

-20x2 = 36x

Solving for variable 'x'.

Reorder the terms:

-36x + -20x2 = 36x + -36x

Combine like terms: 36x + -36x = 0

-36x + -20x2 = 0

Factor out the Greatest Common Factor (GCF), '-4x'.

-4x(9 + 5x) = 0

-4.

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Answer:

24 = x

Step-by-step explanation:

You use Pythagorean theorem. Since the normal equation is a^{2} + b^{2} =c^{2}, you already have the c^{2} and another side which can be a^{2} or b^{2}.

Because you have the hypotenuse and a side , your equation looks like this now: 7^{2} +b^{2} = 25^{2}

and when you solve for be you just subtract 25^{2} -7^{2} to get 24.

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2 years ago
What equation is a linear function?
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c

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3 years ago
Fatima is on the track team. One day at practice, it took her 19 minutes to run 2 miles. Select the expression that gives this a
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Step-by-step explanation:

6 0
3 years ago
If ORBIT is coded BEOVG, then how is PLANET coded? /
arlik [135]

Answer:

1. CYNARG

Step-by-step explanation:

This a example of Caesar's Cipher, in which each letter in the original word leads to a ciphered letter according to the following equation:

C = (P + o) \text{mod} 26

In which C is the index of the Ciphered letter in the alphabet, P is the index of the original letter and o is the offset.

Finding the offset:

O is coded B

O is the 15th letter in the alphabet, so P = 15.

B is the 2nd letter in the alphabet, so C = 2

C = (P + o) \text{mod} 26

2 = (15 + o) \text{mod} 26

|o = |2-15| \text{mod} 26

o = 13

So

C = (P + 13) \text{mod} 26

PLANET:

P

P is the 16th letter in the alphabet.

C = (16 + 13) \text{mod} 26 = 3

So P is coded C.

L

L is the 12th letter in the alphabet:

C = (12 + 13) \text{mod} 26 = 25

L is coded Y(25th letter in the alphabet)

A

A is the 1st letter in the alphabet

C = (1 + 13) \text{mod} 26 = 14

A is coded N

N

N is the 14th letter in the alphabet

C = (14 + 13) \text{mod} 26 = 1

N is coded A

E

E is the 5th letter in the alphabet

C = (5 + 13) \text{mod} 26 = 18

E is coded R

So the correct answer is:

1. CYNARG

4 0
3 years ago
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