Answer:
The upper boundary of the 95% confidence interval for the average unload time is 264.97 minutes
Step-by-step explanation:
We have the standard deviation for the sample, but not for the population, so we use the students t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 35 - 1 = 35
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 34 degrees of freedom(y-axis) and a confidence level of
). So we have T = 2.0322
The margin of error is:
M = T*s = 2.0322*30 = 60.97
The upper end of the interval is the sample mean added to M. So it is 204 + 60.97 = 264.97
The upper boundary of the 95% confidence interval for the average unload time is 264.97 minutes
Answer: Many numbers get ready to write
Step-by-step explanation:
1,30,2,15,3,10,5,6
That is about it I think
So this is what i did but im not sure if its 100% correct
585 / 9 to get the number of groups = 65
then you take 65 x 3 for number of students in each group and you get the final answer of 195 students
<h3>
<u>Explanation</u></h3>

The structure or equation is similar to a quadratic function.
The value of a determines the slope of graph.
Tthe value of h determines the horizontal shift of graph.
The value of k determines the vertical shift of the graph.
From the given equation,

We can say that the graph shifts to the right 2 units and shifts down 7 units. Hence the vertex would be at x = 2 and y = -7. It can be written in coordinate form as (2,-7).
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<u>Answer</u></h3>
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