Answer:
a) 0.6561
b) 0.2916
c) 0.3439
Step-by-step explanation:
We are given the following information:
Let us treat high level of contamination as our success.
p = P(High level of contamination) = P(success) = 0.10
n = 4
The, by binomial distribution:

a) P(No high level of contamination)
We put x = 0, in the formula.

Probability that no lab specimen contain high level of contamination is 0.6561
b) P(Exactly one high level of contamination)
We put x = 1, in the formula.

Probability that no lab specimen contain high level of contamination is 0.6561
c) P(At least one contains high level of contamination)

Probability that at least 1 lab specimen contain high level of contamination is 0.3439