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Leno4ka [110]
3 years ago
5

Which transformation will always produce the same image as a rotation 90° counterclockwise?

Mathematics
1 answer:
monitta3 years ago
8 0

Answer:

b.a rotation 270 clockwise

Step-by-step explanation:

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Help help help ASAP
kirill115 [55]
The answer is: x = 13
8 0
2 years ago
Jar #3 contains 21 gummie bears. How many gummie bears can you get if you can have 1/3 of them
Vlada [557]

Answer:

7 gummy bears

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Need step by step explanation please.
ryzh [129]

1. Volume of 1 tennis ball = volume of sphere = 33.51 in.³

2. Volume of the cylinder = 150.8 in.³

3. Amount of space not occupied by the tennis ball = Volume of cylinder - 3(volume 1 tennis ball) = 50.27 in.³

<h3>What is the Volume of a Cylinder and Volume of a Sphere?</h3>
  • Volume of Cylinder = πr²h
  • Volume of Sphere = 4/3πr³

Diameter of the tennis ball = 4 in. (given)

1. Volume of 1 tennis ball = volume of sphere = 4/3πr³

r = 1/2(4 in.) = 2 in.

Volume of 1 tennis ball = 4/3π(2)³ = 33.51 in.³

2. Volume of the cylinder = πr²h

Radius of the cylinder (r) = 1/2(4 in.) = 2 in

Height of the cylinder (h) = 3(4 in.) = 12 in

Volume of the cylinder = πr²h = π(2²)(12) = 150.8 in.³

3. Amount of space not occupied by the tennis ball = Volume of cylinder - 3(volume 1 tennis ball)

= 150.8 - 3(33.51) = 50.27 in.³

Learn more about volume of a cylinder and a sphere on:

brainly.com/question/64165

4 0
2 years ago
Question 2: ___ of 5 points)
Luba_88 [7]

Answer:

Slope is - 2 because The slope-intercept form is y=mx+b where m is the slope value. In the equation y=-2x , the m value is - 2 .

6 0
3 years ago
Need Help with the composition of two rational functions. screenshot is below
igomit [66]

We just have to write one function inside the other:

(f\circ g)(x) = f(g(x))\\\\(f\circ g)(x) = f\left(\dfrac{13}{x+3}\right)\\\\(f\circ g)(x) = \dfrac{2}{\left(\dfrac{13}{x+3}\right)+3}\\\\(f\circ g)(x) = \dfrac{2}{~~\dfrac{13+3(x+3)}{x+3}~~}\\\\(f\circ g)(x) = \dfrac{2(x+3)}{13+3(x+3)}\\\\\boxed{(f\circ g)(x) = \dfrac{2x+6}{3x+22}}

Since we have a fraction with x in the denominator, we have to remove from the domain the value of  that makes null the denominator. Thus,

3x+22\neq0\Longrightarrow 3x\neq22\Longrightarrow x\neq \dfrac{22}{3}

Furthermore, we also have to remove the value of x that annuls the denominator of g(x), because that's the first function that we use. So:

x+3\neq0\Longrightarrow x\neq-3

Hence, the domain is:

D((f\circ g)(x)) = \left]-\infty,-3\right[\cup \left]-3,\dfrac{22}{3}\right[\cup\left]\dfrac{22}{3},\infty\right[

3 0
4 years ago
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