For the probability distribution shown, what is P (3 < X < 6)?
1 answer:
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Answer:
if ∠Q=∠R
draw an angular bisector from P to QR in which it intersect wit Qr at point S
now we have two triangle : QPS and RSP
in which angle : QPS=RPS ( PS is angular bisector)
and we have angle Q and angle R are equal
and PS is common side
this makes triangle QPS and RSP are congruent by AAS(angle angle side)
which also means that pQ=PR ( proved)
Answer:
Step-by-step explanation:
observe
||a–b+c|| = ||a+b+c||
(a-b+c)² = (a+b+c)²
(a+b+c)² – (a-b+c)² = 0
((a+b+c)+(a-b+c))((a+b+c)–(a-b+c)) = 0
(2a+2c)(2b) = 0
(a+c)b = 0
a•b + c•b = 0
||a||×||b||×cos(π/8) + ||c||×||b||×cos(θ) = 0