Answer:
she messed up on step two because she has to subtract 10 from both sides
Step-by-step explanation:
step 1: -6(x+3)+10<-2
step2:-6(x+3)+10-10<-2-10
step3: -6(x+3)<-12
step4: (-6)(x+3)(-1)≥(-12)(-1)
step5:6(x+3)>12
step6:divide both sides by 6
step7:simplify and subtract 3 from both sides and then simplify again
Answer:
14.4 lb
Step-by-step explanation:
In a see-saw in equilibrium, the torque generated by one side needs to be the same generated in the other side. The torque is calculated by the product between the mass and the distance to the center of the see-saw.
The torque generated by the child is:
T1 = 60 * 3 = 180 lb*feet
So, the torque generated by the weight needs to be higher than T1 in order to lift the child.
The lowest mass is calculated when the mass is in the maximum distance, that is, 12.5 feet from the center.
So, we have that:
T2 = 180 = mass * 12.5
mass = 180/12.5 = 14.4 lb
So the lowest weight is 14.4 lb
Answer:
I dont get it
Step-by-step explanation:
Answer:
Eliminating the parameter, the equation is 
Step-by-step explanation:
We are given the following parametric equations:
We want to eliminate the parameter t. From the first equation:
Replacing in the second equation:
Eliminating the parameter, the equation is
Answer:
The domains are;
0 < x < 3 for f(x) = 15
3 ≤ x ≤ 7 for f(x) = 22
7 < x ≤ 15 for f(x) = 30
Step-by-step explanation:
The duration the amusement park is opened, t = 15 hours
The number of days the amusement is opened = 7 days a week
The prices for the admission are;
x < 3 hours = $15
3 ≤ x ≤ 7 hours = $22
x > 7 hours = $30
The functions are;
f(x) = 15 when x < 3; The domain = 0 < x < 3
f(x) = 22 when 3 ≤ x ≤ 7; The domain = 3 ≤ x ≤ 7
f(x) = 30 when x > 7; The domain = 7 < x ≤ 15.
