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luda_lava [24]
2 years ago
15

If susan, janice, and melvin take 2.0 hours to walk to their school at a rate of 1.0 m/s, how far is their school from their hou

se?
please help me huhu​
Mathematics
1 answer:
RideAnS [48]2 years ago
3 0

Answer:

7.2 km

Step-by-step explanation:

Given that:

Hours taken = 2 hours

Walk rate = 1 m/s

Distance = Speed * time

Time taken in seconds = 2 * 60 * 60 = 7200 s

Hence,

Distance = 1 m/s * 7200s

Distance = 7200 meters

Distance in km = 7200 / 1000 = 7.2 km

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The number of mosquitoes M(x), in millions, in a certain area depends on the June rainfall x, in inches: M(x) = 13 x - x2. What
My name is Ann [436]

Answer:

The number of mosquitoes is maximum for 6.5 inches rainfall.

Step-by-step explanation:

The given function is

M(x)=13x-x^2                   .... (1)

where, M(x) is number of mosquitoes in millions and x the June rainfall in inches.

We need to find the rainfall that produces the maximum number of mosquitoes.

Differential the above function with respect to x.

M'(x)=13-2x               .... (2)

Equate first derivative equal to 0.

13-2x=0

2x=13

x=\frac{13}{2}=6.5

Differential function (2) with respect to x.

M''(x)=-2

Double derivative is negative. So, the value of function is maximum at x=6.5.

Therefore, the number of mosquitoes is maximum for 6.5 inches rainfall.

4 0
3 years ago
Someone plz help me
topjm [15]

x = 375 and y = 6300. Option C.

Step-by-step explanation:

From the given data we need to find the value of x and y.

First, we will find out the ratio of area and the force.

\frac{Area}{Force}  = \frac{125}{1875} =\frac{150}{2250} =\frac{175}{2625} = \frac{1}{15}

So,

\frac{x}{5625} = \frac{1}{15}

or, x = \frac{5625}{15} = 375

Again,

\frac{420}{y} = \frac{1}{15}

or, y = 420×15 = 6300

Hence,

x = 375 and y = 6300.

7 0
3 years ago
((MULTIPLE CHOICE ))
lesya692 [45]

Answer:

Neither.

Step-by-step explanation:

you are correct about the pattern, so it's not adding the same number and not multiplying by the same number. So it's neither.

6 0
3 years ago
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Can someone please help me factor and write the equations for these two problems ?
prisoha [69]

Answer:

Step-by-step explanation:

Asymptotes 3

g(x) = \frac{3x}{x^2-3x-10}

Factors of denominator will be,

x² - 3x - 10 = x² - 5x + 2x - 10

                 = x(x - 5) + 2(x - 5)

                 = (x + 2)(x - 5)

Therefore, factored form of g(x) will be,

g(x) = \frac{3x}{(x + 2)(x - 5)}

Asymptotes 4

h(x) = \frac{(x-5)}{x^{2} + 14x + 40}

      = \frac{x-5}{x^{2}+10x+4x+40}

      = \frac{x-5}{x(x+10)+4(x+10)}

      = \frac{x-5}{(x+10)(x+4)}

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3 years ago
Half of the number, n, plus eight?
3241004551 [841]
Your answer would be A.
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2 years ago
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