The algorithm prints out all the possible ways to draw 3 <span>balls in sequence, </span><span> ---Select--- with </span> <span>replacement. It prints</span> <span>lines.</span>
Well tan x has asymptotes every 90 degrees, or in radian mode, every pi divided by two. since cot is the inverse and the aymsptotes land on every 180 degrees, meaning the equation can be x ≠ \pi n, nEI
Mean = (2+4+6+5+2)/5 = 19/5 = 3.8
answer
<span>C. 3.8</span>
For number 15 and 16, you just have to find the absolute difference between the two points along the calibration of the protractor.
15. ∠BXC = |B - C| = |140° - 110°| = 30°
16. ∠BXE = |B - E| = |140° - 30°| = 110°
For numbers 20 and 21, apply the Angle Addition Postulate. This is when you add the individual interior angles to equate to the total angle.
20. ∠PQS = ∠PQR + ∠RQS
112° = 72°+ 10x°
x = 4
21. ∠KLM = ∠KLN + ∠NLM
135° = 47°+ 16y°
y = 5.5
8x^4 + x^3 - 4x^2 +1. I believe the answer is B. Please correct me if I am wrong.