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Alchen [17]
3 years ago
8

I am looking to decrease my bill by 25%. Can you look at my current plan and tell me what I can remove to achieve this reduction

in cost? My current bill is $140.00 per month
Mathematics
1 answer:
Gennadij [26K]3 years ago
6 0

Answer: $35

Step-by-step explanation:

From the question, we are informed that the current bill of the person is $140.00 per month and that the person wants to decrease the bill by 25%.

To know the amount that the person needs to deduct, we have to calculate 25% of $140.00. This will be:

= 25% of $140

= 25/100 × $140

= 1/4 × $140

= 0.25 × $140

= $35

The person will need to remove $35. The person will now pay ($140 - $35) = $105 monthly.

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if i flip a coin 4 times and i get to 2 heads and 2 tails, how many difenrent ways to get 2 heads and 2 tails.
Assoli18 [71]

Answer:

6

Step-by-step explanation:

-The different ways of two head and two tails in 4 tosses can be determined by drawing the sample space:

THTH\\HTHT\\THHT\\TTHH\\HTTH\\HHTT

-The sample space of the four tosses is as above. Hence, they are 6 different ways  to get 2 heads and 2 tails.

3 0
3 years ago
Find general solutions of the differential equation. Primes denote derivatives with respect to x.
zepelin [54]

Answer:

\mathbf{3x^2y^3+2xy^4=C}

Step-by-step explanation:

From the differential equation given:

6xy^3 +2y ^4 +(9x^2y^2+8xy^3) y' = 0

The equation above can be re-written as:

6xy^3 +2y^4 +(9x^2y^2+8xy^3)\dfrac{dy}{dx}=0

(6xy^3 +2y^4)dx +(9x^2y^2+8xy^3)dy=0

Let assume that if function M(x,y) and N(x,y) are continuous and have continuous first-order partial derivatives.

Then;

M(x,y) dx + N (x,y)dy = 0; this is exact in R if and only if:

\dfrac{{\partial M }}{{\partial y }}= \dfrac{\partial N}{\partial  x}}} \ \ \text{at each point of R}

relating with equation M(x,y)dx + N(x,y) dy = 0

Then;

M(x,y) = 6xy^3 +2y^4\  and \ N(x,y) = 9x^2 y^2 +8xy^3

So;

\dfrac{\partial M}{\partial y }= 18xy^3 +8y^3

       \dfrac{\partial N}{\partial y }

Let's Integrate \dfrac{\partial F}{\partial x}= M(x,y) with respect to x

Then;

F(x,y) = \int (6xy^3 +2y^4) \ dx

F(x,y) = 3x^2 y^3 +2xy^4 +g(y)

Now, we will have to differentiate the above equation with respect to y and set \dfrac{\partial F}{\partial x}= N(x,y); we have:

\dfrac{\partial F}{\partial y} = \dfrac{\partial}{\partial y } (3x^2y^3+2xy^4+g(y)) \\ \\ = 9x^2y^2 +8xy^3 +g'(y) \\ \\ 9x^2y^2 +8xy^3 +g'(y) =9x^2y^2 +8xy^3 \\ \\ g'(y) = 0  \\ \\ g(y) = C_1

Hence, F(x,y) = 3x^2y^3 +2xy^4 +g(y)  \\ \\ F(x,y) = 3x^2y^3 + 2xy^4 +C_1

Finally; the general solution to the equation is:

\mathbf{3x^2y^3+2xy^4=C}

5 0
3 years ago
What is the surface area of a cylinder with a height of 7 and a radius is 3.
kolbaska11 [484]

Answer:

188.5

Step-by-step explanation:

I think that is correct

5 0
3 years ago
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Four teams in a basketball division keep track of the number of points scored per game for the entire basketball season of 22 ga
lubasha [3.4K]
I think the mean is 1 and the mode is 3
4 0
3 years ago
Find the remainder when 3x^3+ 6x-1 is divided by x-3​
Sauron [17]

Answer:

93

Step-by-step explanation:

by remainder theorem p(3) is the remainder

and therefore it is 93

3 0
3 years ago
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