7 1/4 - 2 5/12 = 29
6
= 45
6
≅ 4.833333
For this case we have:
Let
be a given function, where:
- x is an independent variable
- y it is a dependent variable
By definition, the domain of a function is represented by the values associated with the independent variable, that is, the values of x.
Therefore, the domain of the given function is represented by:
![{x | x = -6, -1, 0, 3}](https://tex.z-dn.net/?f=%7Bx%20%7C%20x%20%3D%20-6%2C%20-1%2C%200%2C%203%7D)
Answer:
![{x | x = -6, -1, 0, 3}](https://tex.z-dn.net/?f=%7Bx%20%7C%20x%20%3D%20-6%2C%20-1%2C%200%2C%203%7D)
You can start by constructing a square, drawing the two diagonals and draw a circle from the centre point through the corners.
Or you could start with a circle, draw a diameter, construct a second diameter perpendicular to the first and connect the four circle points to form a square.
I think the question asks for the second method but both give a valid final diagram.
Answer: Please, see the attached file.
Thanks.
Solution:
We can graph using the intercepts:
(1) y-intercept, when x=0
y=4x-3→y=4(0)-3→y=0-3→y=-3
Point=(x,y)=(0,-3)
(2) x-intercept, when y=0
y=4x-3→0=4x-3
Solving for x: Adding 3 both sides of the equation:
0+3=4x-3+3
3=4x
Dividing both sides of the equation by 4:
3/4=4x/4
3/4=x
x=3/4=0.75
Point=(x,y)=(3/4,0)=(0.75,0)
With these pair of points (0, -3) and (0.75,0) we can draw the right line
Answer:
f(x) = 2x² + 3
g(x) = x² - 7
( f - g)(x) = 2x² - x² +3 --7
= x² + 3 + 10
= x² + 10
Hope this helps.