The surviving children would be 66.7% female and 33.3% male. Of the female children, 50% would be expected to be carriers of this gene (like their mother)
| Xg | X
—————-
X | XXg | XX
—————-
Y | XgY | XY
Pretty ugly, but the best punnet square I can do without a link. The offspring with the “g” are those that carry the lethal gene. The male child that carries it will die, but since it is recessive, the female child will live but will be a carrier for this gene. I hope this helps.
<span>Endocytosis is a process for moving items that are outside of the cell into the cytoplasm of the cell. Exocytosis is a process for moving items from the cytoplasm of the cell to the outside.</span>
Answer:
- Parental cross = Cch x chch
- F1 = 1/2 Cch (agouti coat); 1/2 chch (albino coat) >> 1:1 phenotypic ratio
Punnett square:
ch ch
C Cch Cch
ch chch chch
Explanation:
A heterozygous individual is an individual who has two different gene variants (i.e., alleles) at a particular <em>locus</em>. In this case, individuals having the "agouti coat" trait are heterozygous carrying both 'C' and 'ch' alleles. On the other hand, a homo-zygous individual has the same allele at a given <em>locus</em> (here, the 'chch' genotype associated with the albino phenotype). Therefore, as observed in the Punnett Square above, when a heterozygous parent is crossed with a homo-zygous recessive parent for a single gene, alleles segregate in the gametes of both parents so an expected 1:1 phenotypic ratio will be observed.
B: Hunting in packs
The other answers are physical traits.
