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grigory [225]
3 years ago
9

You are driving a metric car that has a speedometer that displays in meters per second. When you look down at your speedometer,

you see that it reads 23 m/s, then 7.4 s later you look down and it reads 13 m/s. What is your average acceleration over those 7.4 s?
Physics
1 answer:
shepuryov [24]3 years ago
7 0
Ahahhabsba babababba ab
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Light hits a clear plastic bottle and a granite rock. Which choice most accurately describes the effect of visible light on the
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#4 is the accurate answer.

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Calculate the energy transfers in joules by a 4kW by appliances left for 2 minutes
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Does passing a magnet through a coil of wire break off it’s electric current
hichkok12 [17]
A magnetic field is actually generated by a moving current (or moving electric charge specifically). The magnetic field generated by a moving current can be found by using the right hand rule, point your right thumb in the direction of current flow, then the wrap of your fingers will tell you what direction the magnetic field is. In the case of current traveling up a wire, the magnetic field generated will encircle the wire. Similarly electromagnets work by having a wire coil, and causing current to spin in a circle, generating a magnetic field perpendicular to the current flow (again right hand rule).

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Source: Bachelor's degree in Physics.
7 0
3 years ago
A car rolls backward from -2 to -10 m/s in 4 seconds. what is the acceleration. PLEASE HELP WILL GIVE BRAINLIEST
pashok25 [27]

\bf \underline{Given : }

  • Initial velocity,u = -2 m/s

  • Final velocity,v = -10 m/s

  • Time taken, t = 4 seconds

\bf \underline{To  \: find  \: out : }

Find the acceleration ( a ) .

\bf \underline{Solution : }

We know that,

\sf \: Acceleration =  \dfrac{v - u}{t}

Substituting the values in the above formula, we get

\implies \sf \: Acceleration =  \dfrac{ - 10 - ( - 2)}{4}

\implies\sf \: Acceleration =  \dfrac{ - 10 + 2}{4}

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\implies\sf \: Acceleration =  - 2 \: ms {}^{ - 2}

Hence,the acceleration of a body is -2 m/s².

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4 years ago
If root-mean-square voltage of a supply is 240 V, calculate the maximum voltage of
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Answer:

Vp= Vr sq. root 2

= 240 × sq. root 2

=339.4 V

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