The student can measure a liquid's volume by using a graduated cylinder, or a beaker. Mass can be measured by first weighing an empty container on a scale, and then by adding the liquid to the container and weighing it again.
By Newton's second law, the net force on the object is
∑ <em>F</em> = <em>T</em> - <em>mg</em> = - <em>ma</em>
where
• <em>T</em> = 25 N, the tension in the string
• <em>m</em> is the mass of the object
• <em>g</em> = 9.8 m/s², the acceleration due to gravity
• <em>a</em> = 2.0 m/s², the acceleration of the elevator-object system
Solve for <em>m</em> :
25 N - <em>m</em> (9.8 m/s²) = - <em>m</em> (2.0 m/s²)
==> <em>m</em> = (25 N) / (9.8 m/s² - 2.0 m/s²) ≈ 3.2 kg
The characteristic that gives an element its distinctive properties is its number of protons because the number of protons of any element represents its atomic number.
<h3>What is the atomic number?</h3>
The total number of protons present in an atom is known as the atomic number of that atom. The atomic number has no correlation either with the number of neutrons or the number of electrons present inside an atom.
Since the number of protons in any element corresponds to its atomic number, this property provides an element with its particular features.
Learn more about the atomic number from here,
brainly.com/question/14190064
#SPJ4
Answer:
The reading of Y is -10°.
Explanation:
For scale X, the ice point is 40° and steam point is 120°.
Difference between the two extremes for scales X = 120 - 40 = 80
For scale X, the ice point and steam points are -30° and 130° respectively.
Difference between the two extremes for scales X = 130 - (-30) = 160
Comparing both scales:
One unit of scale X = x
One unit of scale Y = y
Scale X has 80 divisions while scale Y has 160
80x = 160y
x = 2y
50° in scale X = 10x + ice point in X scale
10 divisions in Y scale = 20y
Reading of Y scale = ice point of Y + 20y
= -30° + 20°
= -10°
Answer:
a. 3.6 units
b. 1.4 units
c. 3.6 units
d. 6.1 units
Explanation:
The length of a vector is given by the following formula:
Length = √(x² + y²)
where,
x = x-component of vector
y = y-component of vector
a.
Here,
x = 2
y = 3
Therefore,
Length = √(2² + 3²)
Length = √13
<u>Length = 3.6 units</u>
<u />
b.
Here,
x = 1
y = 1
Therefore,
Length = √(1² + 1²)
Length = √2
<u>Length = 1.4 units</u>
<u />
c.
Here,
x = 2
y = -3
Therefore,
Length = √(2² + (-3)²)
Length = √13
<u>Length = 3.6 units</u>
<u />
d.
Here,
x = 1
y = -6
Therefore,
Length = √(1² + (-6)²)
Length = √37
<u>Length = 6.1 units</u>
