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Novay_Z [31]
3 years ago
8

A person is pulling a wagon of heavy rocks for the garden with a force of 12 N. Another person wants to help and pushes the wago

n from behind with a force of 8 N. The frictional force is 6 N. What is the net force on the wagon?
Physics
1 answer:
Mariulka [41]3 years ago
7 0

Answer:

If I'm correct the answer is 14N

Explanation:

Because both of the People are pushing the same direction so you would add both of there Net forces together. Then you would have to subtract the frictional force from 20 to get 14

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<em>or</em><em>,</em><em> </em><em>I</em><em> </em><em>=</em><em> </em><em>V</em><em>/</em><em>R</em>

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<em>(</em><em>A</em><em>=</em><em> </em><em>ampere</em><em> </em><em>=</em><em> </em><em>unit</em><em> </em><em>of</em><em> </em><em>current</em><em>)</em><em>.</em>

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6 0
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Una persona A tiene cierta cantidad de masa y una persona B tiene la mitad de masa de la persona A ¿como es el peso de B respect
musickatia [10]

Answer:

El peso de la persona B es la mitad del peso de la persona A.

Explanation:

El peso de la persona B puede calcularse con la siguiente ecuación:

P_{B} = m_{B}g   (1)

En donde:

m_{B}: es la masa de la persona B

g: es la gravedad

Dado que la persona B tiene la mitad de la masa de la persona A, tenemos:

m_{B} = \frac{m_{A}}{2}  (2)

En donde:

m_{A}: es la masa de la persona A

Al introducir la ecuación (2) en (1) nos queda:

P_{B} = \frac{m_{A}}{2}g   (3)

Sabemos que el peso de la persona A está dado por:

P_{A} = m_{A}g   (4)

Entonces, al introducir la ecuación (4) en (3) tenemos:

P_{B} = \frac{P_{A}}{2}

Por lo tanto, el peso de la persona B es la mitad del peso de la persona A.

Espero que te sea de utilidad!

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7 0
3 years ago
Read 2 more answers
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