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2 years ago

20 POINTS!!!!!

Mathematics

2 answers:

Alexus [3.1K]2 years ago

7 0

Answer:

Step-by-step explanation:

It was 12 take away 210 add 20 to 3243

aleksandr82 [10.1K]2 years ago

5 0

Answer:

1 and 21

Step-by-step explanation:

-12, 1 , 10 , 21 , 32, 43

43-32 is 11

32-11=21

21-11 is 11

10-11 is 1

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For each of parts (a) through (d), indicate whether we would generally expect the performance of a flexible statistical learning

olga_2 [115]

Step-by-step explanation:

First, note that a flexible statistical learning method refers to using models that take into account agree difference in the observed data set, and are thus adjustable. While the inflexible method usually involves a model that has no regard to the kind of data set.

a) The sample size n is extremely large, and the number of predictors p is small. (BETTER)

In this case since the sample size is extremely large a flexible model is a best fit.

b) The number of predictors p is extremely large, and the number of observations n is small. (WORSE)

In such case overfiting the data is more likely because of of the small observations.

c) The relationship between the predictors and response is highly non-linear. (BETTER)

The flexible method would be a better fit.

d) The variance of the error terms, i.e. σ2=Var(ϵ), is extremely high. (WORSE)

In such case, using a flexible model is a best fit for the error terms because it can be adjusted.

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3 years ago

The bill at a restaurant is $28.48, not including tax. A family wants to leave an 18% tip. How much money

Nezavi [6.7K]

Answer:

5.13

Step-by-step explanation:

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3 years ago

Christine Wong has asked Dave and Mike to help her move into a new apartment on Sunday morning. She has asked them both in case

olga nikolaevna [1]

Answer:

(a) The probability that both Dave and Mike will show up is 0.25.

(b) The probability that at least one of them will show up is 0.75.

Step-by-step explanation:

Denote the events as follows:

<em>D</em> = Dave will show up.

<em>M</em> = Mike will show up.

Given:

$P(D^{c})=0.55\\P(M^{c})=0.45$

It is provided that the events of Dave of Mike showing up are independent of each other.

(a)

Compute the probability that both Dave and Mike will show up as follows:

$P(D\cap M)=P(D)\times P (M)\\=[1-P(D^{c})]\times [1-P(M^{c})]\\=[1-0.55]\times[1-0.45]\\=0.2475\\\approx0.25$

Thus, the probability that both Dave and Mike will show up is 0.25.

(b)

Compute the probability that at least one of them will show up as follows:

P (At least one of them will show up) = 1 - P (Neither will show up)

$=1-P(D^{c}\cup M^{c})\\=P(D\cup M)\\=P(D)+P(M)-P(D\cap M)\\=[1-P(D^{c})]+[1-P(M^{c})]-P(D\cap M)\\=[1-0.55]+[1-0.45]-0.25\\=0.75$

Thus, the probability that at least one of them will show up is 0.75.

(c)

Compute the probability that neither Dave nor Mike will show up as follows:

$P(D^{c}\cup M^{c})=1-P(D\cup M)\\=1-P(D)-P(M)+P(D\cap M)\\=1-[1-P(D^{c})]-[1-P(M^{c})]+P(D\cap M)\\=1-[1-0.55]-[1-0.45]+0.25\\=0.25$

Thus, the probability that neither Dave nor Mike will show up is 0.25.

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3 years ago

Read 2 more answers

I will make u a brainliest plz help me

satela [25.4K]

Answer: B) Infinitely many solutions; both equations are equivalent

==============================================================

Work Shown:

x+y = 4 ... start with the first equation

x + (-x+4) = 4 ... replace y with (-x+4)

x-x+4 = 4

0x+4 = 4

0+4 = 4

4 = 4 ... this is a true statement regardless of what x you pick

So there are infinitely many solutions. Each solution (x,y) is of the form (x,-x+4). All solutions fall on the line y = -x+4 which is equivalent to x+y = 4. Note how we add x to both sides.

Or you could start with x+y = 4 and subtract x from both sides to get y = -x+4. Either way, we're dealing with the same equation which is why they both graph out the same line.

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3 years ago

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In ΔEFG, e = 4.7 inches, f = 4.8 inches and g=3.6 inches. Find the measure of ∠E to the nearest 10th of a degree.

AleksAgata [21]

Answer:

66.3

Step-by-step explanation:

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3 years ago