Answer:
0.09852 seconds
Explanation:
= Linear density = 0.0292 kg/m
= Tesnsion in string A = ![33\times 10^2\ N](https://tex.z-dn.net/?f=33%5Ctimes%2010%5E2%5C%20N)
= Tesnsion in string B = ![3.76\times 10^2\ N](https://tex.z-dn.net/?f=3.76%5Ctimes%2010%5E2%5C%20N)
t = Time taken till the pulses pass each other
Velocity of wave in a string is given by
![v_A=\sqrt{\dfrac{T_A}{\mu}}\\\Rightarrow v_A=\sqrt{\dfrac{33\times 10^2}{0.0292}}](https://tex.z-dn.net/?f=v_A%3D%5Csqrt%7B%5Cdfrac%7BT_A%7D%7B%5Cmu%7D%7D%5C%5C%5CRightarrow%20v_A%3D%5Csqrt%7B%5Cdfrac%7B33%5Ctimes%2010%5E2%7D%7B0.0292%7D%7D)
![v_B=\sqrt{\dfrac{T_2}{\mu}}\\\Rightarrow v_B=\sqrt{\dfrac{3.76\times 10^2}{0.0292}}](https://tex.z-dn.net/?f=v_B%3D%5Csqrt%7B%5Cdfrac%7BT_2%7D%7B%5Cmu%7D%7D%5C%5C%5CRightarrow%20v_B%3D%5Csqrt%7B%5Cdfrac%7B3.76%5Ctimes%2010%5E2%7D%7B0.0292%7D%7D)
![Distance=Speed\times Time](https://tex.z-dn.net/?f=Distance%3DSpeed%5Ctimes%20Time)
![L=(v_A+v_B)t\\\Rightarrow t=\dfrac{L}{v_A+v_B}\\\Rightarrow t=\dfrac{44.3}{\sqrt{\dfrac{33\times 10^2}{0.0292}}+\sqrt{\dfrac{3.76\times 10^2}{0.0292}}}\\\Rightarrow t=0.09852\ s](https://tex.z-dn.net/?f=L%3D%28v_A%2Bv_B%29t%5C%5C%5CRightarrow%20t%3D%5Cdfrac%7BL%7D%7Bv_A%2Bv_B%7D%5C%5C%5CRightarrow%20t%3D%5Cdfrac%7B44.3%7D%7B%5Csqrt%7B%5Cdfrac%7B33%5Ctimes%2010%5E2%7D%7B0.0292%7D%7D%2B%5Csqrt%7B%5Cdfrac%7B3.76%5Ctimes%2010%5E2%7D%7B0.0292%7D%7D%7D%5C%5C%5CRightarrow%20t%3D0.09852%5C%20s)
The time taken is 0.09852 seconds
Answer: I want to say car Z because it is the smallest and smaller cars are usually more aerodynamic.
Explanation:
Answer:150Nm
Explanation:
Force=50.0N distance=3.00m
Work=force x distance
Work=50 x 3
Work=150Nm
Simple, A. None of the other answers make sense so, A.
Explanation:
10
/9 Ω
potential difference across the cell in open circuit is the emf of the cell.
Hence, emf E=2.2V
when, circuit is closed, potential difference across cell is given by V=E−Ir
And,
I= E/
R+r
Hence, V= E− Er/
R+r
⟹ V= ER/
R+r
⟹ 1.8= 2.2×5
/5+r
⟹9+1.8r=11
⟹ r= 2/ 1.8 Ω
⟹ r= 10/9 Ω