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Kamila [148]
3 years ago
11

A voltage of 21.0V across the terminals of a device produces a current of 3.00 mA through the device. What is the resistance of

the device?
Physics
1 answer:
densk [106]3 years ago
8 0

Answer: 7,000 ohms

Explanation:

From the equation of ohms law V= IR

V=21 volt

I = 3 MA = 3.0×10^-3 A

So by evaluating, we have.

V= IR

21= 3.0×10^-3 × R

Then R = 21/3.0×10^-3

R= 7,000 ohms//.

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The potential difference across a and b is 15 v. determine the electrical charge on the 3 μf capacitor will be 45 *  10^{-6} C

Capacitance, property of an electric conductor, or set of conductors, that is measured by the amount of separated electric charge that can be stored on it per unit change in electrical potential. Capacitance also implies an associated storage of electrical energy.

Charge (Q) stored in a capacitor is the product of its capacitance (C) and the voltage (V) applied to it. The capacitance of a capacitor should always be a constant, known value. So we can adjust voltage to increase or decrease the cap's charge. More voltage means more charge, less voltage... less charge.

charge = capacitance * voltage

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To learn more about capacitance here

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