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3 years ago

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Please help me !! i am tired i worked all day to bring my grade up whitch i did i just gotta do this last assiment I will give b

rainlsit when i wake up

1 answer:

Anvisha [2.4K]3 years ago

7 0

Plutonium= Pu, 94, 244,94,94

Chromium= Cr, 24,52, 24,24

Neon = Ne, 10,20,10,10

Gold= Au, 79,197,79,79

Radon = Ra ,86,222,86,86

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Water can be found in solid, liquid, and gaseous states. Which two processes would result in water changing to water vapor (or s

slava [35]

Answer:

sublimation and evaporation

Explanation:

evaporation is from liquid to gas and sublimation is solid to liquid, as water vapor is a gas both of these methods could be used

4 0

3 years ago

what is the resistance of a 12m long wire having radius( 2*10 to the power - 4) and resistivity (3.14*10 to the power - 8)ohmM

Arisa [49]

R = ρl/A

Where R = Resistance in Ohms, Ω, ρ = Resistivity in Ωm, l = Length in m.

Area in m²

ρ = Resistivity = 3.14 * 10⁻⁸ Ωm, Length l = 12m,

Area = πr² = π* (2*10⁻⁴)² m² ≈ 3.14 * (2*10⁻⁴)² m²

R = ρl/A

≈ 3.14 * 10⁻⁸ * 12 / (3.14 * (2*10⁻⁴)²)

≈ 3

Resistance, R ≈ 3 Ω

3 0

3 years ago

Pls look at the photo above, thanks

frosja888 [35]

V=s/t. All you need to do is
s=v×t=330×1.8

4 0

3 years ago

A man (weighing 763 N) stands on a long railroad flatcar (weighing 3513 N) as it rolls at 19.8 m/s in the positive direction of

Burka [1]

Answer:

0.8m/s

Explanation:

Weight of mas,F=763 N

Mass of man= $\frac{F}{g}=\frac{763}{9.8}=77.86 kg$

By using $g=9.8m/s^2$

Weight of flatcar=F'=3513 N

Mass of flatcar= $\frac{3513}{9.8}=358.5 Kg$

Total mass of the system=Mass of man+mass of flatcar=77.86+358.5=436.36 kg

Velocity of system=19.8m/s

Let v be the velocity of flatcar with respect to ground

Velocity of man relative to the flatcar= $-4.68m/s$

Final velocity of man with respect to ground=v-4.68

By using law of conservation of momentum

Initial momentum=Momentum of car+momentum of flatcar

$436.36(19.8)=77.86(v-4.68)+358.5v$

$8639.928=77.86v-364.3848+358.5v$

$8639.928+364.3848=436.36 v$

$9004.3128=436.36v$

$v=\frac{9004.3128}{436.36}$

$v=20.6 m/s$

Initial speed of flatcar=Speed of system

Increase in speed=Final speed-initial speed=20.6-19.8=0.8m/s

4 0

3 years ago

The horse on a carousel is 3.5m from the central axis.A. If the carousel rotates at 0.13 rev/s , how long does it take the horse

Kitty [74]

Answer:

a. 15.4 seconds

b. 0.455 m/s

Explanation:

a. The carousel rotates at 0.13 rev/s.

This means that it takes the carousel 1 sec to make 0.13 of an entire revolution.

This means that time it will take to make a complete revolution is:

1 / 0.13 = 7.7 seconds

Therefore, the time it will take to make 2 revolutions is:

2 * 7.7 = 15.4 seconds

b. Let us calculate the linear velocity. Angular velocity is given as:

$\omega = v / r$

where v = linear velocity and r = radius

The radius of the circle is 3.5 m and the angular velocity is 0.13 rev/s, therefore:

0.13 = v / 3.5

v = 3.5 * 0.13 = 0.455 m/s

Linear velocity is 0.455 m/s

8 0

3 years ago